Answer:
(a) 
(b) 
Explanation:
Hello,
In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:
Thus, since the final pressure is 3.60 bar, we can write:
The moles of helium could be computed via solver as:
Or algebraically:
In such a way, the volume of the compartment B is:
Finally, he mole fraction of He is:
Regards.
Balance Chemical Equation,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO
Solving for X,
X = (56 g × 24.7 g) ÷ 88 g
X = 2.26 g ÷ 88 g
X = 0.0257 g of CO
Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
I believe the answer is two
Answer:
C = 0.08M
Explanation:
molar mass of AlCl3
Al =27
Cl = 35.5
27+3(35.5) =133.5g/mol
n= mass/Molar mass
n =CV
CV = mass/molar mass
C x 500 x 10^-³ = 5/133.5
C x 500 x 10^-³ = 0.04
C = 0.04/500 x 10^-³
C = 0.08M
Answer:
True
Explanation:
Yes I agree object can be in motion and in not motion at the same time for example there are two men travelling on the bus one person is A another person is B. the person be B rest so by seeing person be the person A also sits but the person see who saw the person be B move along with person C so the the person be B is in rest for person Abut is motion for a person C.
