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Vikentia [17]
2 years ago
6

Which training does Michael need to work as a veterinarian in a zoo? Michael loves animals, so he studied to become a veterinari

an. However, he wishes to work for a well-known zoo in Ohio. He would probably need to acquire training in zoo { } to be hired.
Biology
1 answer:
Bumek [7]2 years ago
3 0

The training that Michael need to work as a veterinarian in a zoo is to acquire a degree in veterinary medicine.

<h3>Who is a veterinarian?</h3>

A veterinarian is a professional that has passed through a training institution for the purpose of being trained in the area of animal health.

There are different fields in veterinary medicine which Include the following:

  • Companion Animal Veterinarians.

  • Veterinary Practitioners.

  • Food Animal Veterinarians.

  • Food Safety and Inspection Veterinarians.

  • Research Veterinarians.

Learn more about veterinary here:

brainly.com/question/7982337

#SPJ1

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Organisms with the genotypes aabbccdd and aabbccdd are crossed. What are the expected proportions of the following progeny?
Dvinal [7]

Answer:

a) \frac{27}{64}

b)\frac{1}{32}

c) \frac{27}{64}

d) \frac{3}{64}

Explanation:

The correct question is

Organisms with the genotypes AABbCcDd and AaBbCcDd are crossed. What are the expected proportions of the following progeny?

a. A_B_C_D_

b. AabbCcDd

c. a phenotype identical to either parent

d. A_B_ccdd

Solution

In such question the probability for each allele pair is to be determines separately

For instance,

AA * Aa will produce AA, Aa, AA, Aa this means that all the the probability of getting both AA and Aa is \frac{1}{2}

Like wise when Bb and Bb are crossed, BB, Bb, Bb, and bb are produced. So the probability of getting dominant trait i.e BB or Bb is \frac{3}{4} and recessive trait i.e bb is \frac{1}{4}

Chance to get homozygous bb only or BB only is \frac{1}{4}

and chance of getting Bb is  \frac{1}{2}

Like Bb and Bb cross, the same will be the probabilities for Cc and Cc cross and Dd and Dd cross

Part A)

\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}

Part B)

\frac{1}{4} * \frac{1}{2} *  \frac{1}{2}*  \frac{1}{2}\\=  \frac{1}{32}

Part C)

\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}

Part D)

\frac{3}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{3}{64}

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