Question

Please Show your work, equations, etc. I will name Brainliest!!!! (: A pyramid has a square base that measures 10 feet on a side. The height of each face is five feet. What is the surface area of the pyramid?

Answer 1

Answer:

$\boxed{\sf 200 \ feet^2}$

Step-by-step explanation:

The 3D shape is a square-based pyramid.

The surface area of a square-based pyramid is given as:

$\sf SA=2 \times (base \ length) \times (slant \ height) + (base \ length)^2$

Plug in the values.

$\sf SA=2 \times 10 \times 5 + 10^2$

$\sf SA=100 + 100$

$\sf SA=200$

Answer 2

Answer:

200 ft^2

Step-by-step explanation:

The surface area of the pyramid is the sum of the area of the base and the areas of the 4 congruent triangular sides.

SA = LW + 4 * bh/2

SA = 10 ft * 10 ft + 4 * (10 ft)(5 ft)/2

SA = 100 ft^2 + 2(50 ft^2)

SA = 200 ft^2

(P.S. It's impossible to make a pyramid with these dimensions.)