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Solve the equation:
Reduce the fractions at the left side so that they have the same denominator:
Numerators must be equal:
I hope this helps. =)
Tags: <em>rational equation fraction solution algebra</em>
Answer:
150
Step-by-step explanation:
us I'd send bag I'd send veg svdudhvgdkdbdbdudduddh
Answer:
3.04
Step-by-step explanation:
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Answer:
If this is the complete question them the answer is 1250 m²
Step-by-step explanation:
the pool in the drawing is 15x7.5 and the scale is 3/1000 so if the size in the drawing is 3 then the actual is 1000.
x=15*1000/3=5000cm which would be 50m
x=7.5*1000/3=2500cm which is 25m
the actual area of the pool is 50*25=1250 m²
