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Nutka1998 [239]
2 years ago
15

Percent yields are generally calculated from masses. Would the result be the same if amounts (mol) were used instead? Why?

Chemistry
1 answer:
rusak2 [61]2 years ago
7 0

Using the mole ratio from the balanced chemical equation, we can determine the theoretical yield of product. We convert each initial amount of reactant to product.

Yes , the result would be same .

Is experimental and actual yield the same?

It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%. If the actual and theoretical yield ​are the same, the percent yield is 100%. Usually, percent yield is lower than 100% because the actual yield is often less than the theoretical value

What Is percent yield?

Percent yield is the percent ratio of actual yield to the theoretical yield. It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%. If the actual and theoretical yield ​are the same, the percent yield is 100%.

             Percent yield = \frac{Actual yield}{theoretical yield} ×100 %

Learn more about percent yield :

brainly.com/question/11963853

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Barium has a body-centered cubic structure. If the atomic radius of barium is 222 pm, calculate the density of solid barium?
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Answer: density =3.377g/cm³

Explanation:

Density =( molecular weight × effective number of atoms per unit cell) / (volume of unit cell × avogadro constant)

D= (M ×n) /(V×A)

M= 137g/mol

n= 2 (For BCC)

V=a³ , where a= 4r/√3

a= (4×222)/√3

a=512.69pm

a= 512.69×10^-10cm

V= ( 512.69×10^-10)^3

V= 1.3476×10^-22cm³

D= (137×2)/(1.3476×10^-22 × 6.02^23)

D= 3.377g/cm³

Therefore the density of barium is 3.377g/cm³

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When iron react with oxygen gas to give iron oxide. This process is known as iron rusting. During the reaction, oxidation-reduction process occurs.

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