Answer:
34.9 g of Zn(OH)₂ is the maximum mass that can be formed
Explanation:
Let's state the reaction:
ZnO(s) + H₂O(l) → Zn(OH)₂ (aq)
First of all, we need to determine the moles of each reactant and state the limiting:
28.6 g . 1mol /81.38 g = 0.351 moles of ZnO
9.54 g . 1mol /18 g = 0.53 moles of water
As ratio is 1:1, for 0.53 moles of water, we need 0.53 moles of ZnO, but we only have 0.351, so the limiting reactant is the ZnO.
Ratio with the product is also 1:1. From 0.351 moles of oxide we can produce 0.351 moles of hydroxide. Let's calculate the mass:
0.351 mol . 99.4 g /1mol = 34.9 g
Answer:
80g=0.08kg
20cm=0.02m
density=m/v
= 0.08/0.02
=4kg/m^3
it is less than density of water so it floats
What do you need help with exactly can you explain ? I think I understand what you mean cause I just had this assignment in chemistry
Answer:
A) 3.17 g of Zn
Explanation:
Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.
Zn⁺²(aq) + 2e⁻ → Zn(s)
We can establish the following relations:
- 1 min = 60 s
- 1 A = 1 C/s
- The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
- When 2 moles of electrons circulate, 1 mole of Zn is deposited.
- The molar mass of Zn is 65.38 g/mol
The mass of Zn deposited under these conditions is:
