Answer:
1 - Weak electrolyte
2- Non electrolyte
3- Weak electrolyte
4- Strong electrolyte
Explanation:
A strong electrolyte refers to an electrolyte that decomposes completely in solution. This means that there are more charge carriers in solution when a strong electrolyte is dissolved in water. A strong electrolyte produces a strong glow. LiOH is a strong electrolyte.
A weak electrolyte is not completely dissociated in water. Only a small amount dissociates in water. HF is a weak electrolyte. A weak electrolyte does not produce a bright light.
A non-electrolyte does not dissociate in solution at all hence it does not power a bulb E.g C12H22O11.
Answer:
Chemical equation:
HNO₃ + Al(OH)₃ → Al(NO₃)₃ + H₂O
Explanation:
Chemical equation:
HNO₃ + Al(OH)₃ → Al(NO₃)₃ + H₂O
Balanced chemical equation:
3HNO₃ + Al(OH)₃ → Al(NO₃)₃ + 3H₂O
Ionic equation:
3H⁺ + 3NO⁻₃(aq) + Al(OH)₃(s) → Al³⁺(aq) + 3NO₃⁻¹(aq) + 3H₂O(l)
Net ionic equation:
Al(OH)₃(s) + 3H⁺(aq) → Al³⁺(aq) + 3H₂O(l)
The NO⁻₃ are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
Answer:
The correct answer is AMP+H2O→ Adenosine + pi
Explanation:
The above reaction is least energetic because there is no phosphoanhydride bond present with adenosine mono phosphate.Phospho anhydride bond is an energy rich bond.
As a result hydrolysis of AMP generates very little amount of energy in comparison to the hydrolysis of ATP and ADP.
Answer:
you can solve the rest of the equation. I only reduced it to that much to show you how to derive it
If I'm correct the answer should be a series circuit :) Hopefully this helps you out