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bixtya [17]
3 years ago
5

During the phase change from solid ice to liquid water, which bonds/forces are being weakened?

Chemistry
1 answer:
kvasek [131]3 years ago
5 0
INTERmolecular forces (such as dipoles and London dispersion forces).

The actually compound isn't changing (it's still H2O in solid or liquid form), so INTRAmolecular bonds aren't being affected. It's just the strength of attraction between separate molecules that is weakening.
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Read 2 more answers
- How many moles of H2O are required to react to form 2.5 grams of CH ?
abruzzese [7]

Answer:

0.312 moles of H2O

Explanation:

no. of moles of ch4= mass ÷ molar mass

                               =2.5 ÷ 16.04

                               =0.156 moles of ch4

According to balanced chemical equation

CH4        :        H2O

1 mole     :        2 moles

0.156 moles :       x moles  

by cross multiplication

x=  (0.156x2) ÷ 1

 = 0.312 moles of H2O

7 0
3 years ago
Will the calculated Molarity of NaOH be too high or too low or unaffected if the following happen: when you answer the question,
vodomira [7]

Answer:

Explanation:

The result will be affected.

The mass of KHP  weighed out was used to calculate the moles of KHP weighed out (moles = mass/molar mass).

Not all the sample is actually KHP if the KHP is a little moist, so when mass was used to determine the moles of KHP, a higher number of moles than what is actually present would be obtained (because some of that mass was not KHP but it was assumed to be so. Therefore, there is actually a less present number of moles than the certain number that was thought of.

During the titration, NaOH reacts in a 1:1 ratio with KHP. So it was determined that there was the same number of moles of NaOH was the volume used as there were KHP in the mass that was weighed out. Since there was an overestimation in the moles of KHP, then there also would be an overestimation in the number of moles of NaOH.

Thus, NaOH will appear at a higher concentration than it actually is.

7 0
3 years ago
How many liters of solvent are needed to make a 6.5M solution with 34 mol of solute?
Dominik [7]

Answer:

5.231 L.

Explanation:

  • Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of KCl)/(Volume of the solution (L))</em>

<em></em>

M = 6.5 M.

no. of moles of solute = 34.0 mol,

Volume of the solution = ??? L.

∴ (6.5 M) = (34.0 mol)/(Volume of the solution (L))

∴ (Volume of the solution (L) = (34.0 mol)/(6.5 M) = 5.231 L.

6 0
3 years ago
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