Answer:
1. 35
2. 145
3. 55
4. 90
5. 145
Step-by-step explanation:
1. 35: angle 1 and 2 are a linear pair (meaning it is in one line and adds to 180). Since we know angle 2 is 145, ∠1 = 180 - 145
∠1 = 35
2. 145: ∠7 = ∠2 because they are alternate angles and alternate angles are equal
3. 55: ∠7 = ∠5 + ∠4 because vertically opposite angles are equal. We know that ∠5 = 90, hence ∠4 would equal 145 - 90 = 55
4. ∠5 = 90. It is given
5. 145: ∠9 = ∠2 because they are vertically opposite
Answer:
x=0
y=6
Step-by-step explanation:
Two equations with two unknowns can be solved. Use the three steps given below.
In general you can save time if you use the simplest expression for step 1. You can choose either expression to start with x =.. or you can rewrite it, so it starts with y =...
FOLLOW THESE STEPS:
1. Rewrite the first expression so it starts with y =...
2. Then use that expression and substitute it in the other expression, to find the value for x.
3. Use that value found in step 2. and substitute it in the rewritten expssion you created in step 1. Solve this last expression and you'll get the value for y.
Step 1.
-6y + 11x = -36
-6y = -11x -36
multiply left and right of the = sign by -1
6y = 11x + 36
divide left and right of the = sign by 6
y = 11x/6 + 36/6
y = 11/6x + 6
Step 2.
-4 * ( y ) + 7x = -24
-4 * ( 11/6x + 6 ) + 7x = -24
( -44/6x - 24 ) + 7x = -24
-44/6x + 7x = -24 + 24
You can see immediately that ...x = 0
Just for fun of it ....
-44/6x + 42/6x = 24 - 24
(-44+42)/6x = 0
-2/6x = 0
-1/3x = 0
multiply left and right of the = sign by -3
3/3x = 0 * -3
x = 0
Step 3.
y = 11/6( x ) + 6. and substitute x = 0 gives:
y = 11/6( 0) + 6
y = 0 + 6
y = 6
A= 20 cause 5-2=3 and if the top is 23 it has to be 20
To estimate the distance between the tip of his fishingrod which is above the water and the hook which is below the water, you will need to estimate the absolute values of both distances.
|53 3/4| + |12 2/3|54 + 1367 ft
Trents estimate is not reasonable because you would around both of these values up to the next whole number making it greater than 65.
