A quarterback on a football team throws the football down the field. The height (h) in feet of the ball when it has traveled a h orizontal distance of x yards is given by the quadratic function
1 answer:
Use the equation t = -b / (2a) where: a = -16 b = 30.4 Plug these values into the equation. b) Evaluate h(t) at the time of maximum height. The time of maximum height is the value found in previous part. c) Set h(t) equal to 3 and solve for t. 3 = -16t2 + 30.4t + 5 0 = -16t2 + 30.4t + 2 Solve this quadratic equation for t. I suggest you use the quadratic formula to solve for.
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10 x 7 = 70 1 x 7 = 7 9 x 7 = 70 - 7 9 x 7 = 63
Answer:
3. 8y= -7x -12
4. -3y= 4x -12
5. 7y= -2x +4
Do you want me to do the rest?
did you got it??
The rest are:
6. -3y =6x +12
7. -10y= 5x+20
8. 4y=2x +12
Step-by-step explanation:
7z-5=4y-6
-4y=-6-7z+5
-4y=-1-7z
y=1/4+7/4z
y=7/4z+1/4
7z=4y-6+5
7z=4y-1
z=4/7y-1/7
So basically they are all negatives... positive and negative make negative you add them and put a negative in front.... -25-12-34 add them -37-34 = -71
20% of 106
= 0.20 * 106
= 21.2
21.2 = 10.6% of 21.2 / 0.106
= 200 answer
2. 56 * 0.055 / 0.35
= 8.8
3. 6.4 / 0.8 = 8