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3 years ago

HELPPPPPPPPPPPP PLEASEEEEEEEEE!!!!!!!!

Mathematics

2 answers:

RSB [31]3 years ago

3 0

Answer:

Step-by-step explanation:

a line adds up to 180 so 180-133=47

love history [14]3 years ago

3 0

Answer:

m<GFN= 90° a right angle

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Please help, I have no idea what it's asking :')

Andre45 [30]

the answer is step by step CFE

3 0

3 years ago

Put these points into an equation IN STANDARD FORM!!!!!!<br><br>(0,2) and (8,0)

zubka84 [21]

The equation of the line in standard form is x + 4y = 8

<h3>How to determine the line equation?</h3>

From the question, the points are given as

(0, 2) and (8, 0)

To start with, we must calculate the slope of the line

This is calculated using

Slope = (y₂ - y₁)/(x₂ - x₁)

Where

(x, y) = (0, 2) and (8, 0)

Substitute the known parameters in Slope = (y₂ - y₁)/(x₂ - x₁)

So, we have

Slope = (0 - 2)/(8 - 0)

Evaluate

Slope = -1/4

The equation of the line can be calculated using as

y - y₁ = m(x + x₁)

Where

(x₁, y₁) = (0, 2)

and

m = slope = -1/4

Substitute the known values in the above equation

So, we have the following equation

y - 2 = -1/4(x - 0)

This gives

y - 2 = -1/4x

Rewrite as

1/4x + y = 2

Multiply by 4

x + 4y = 8

Hence, the line has an equation of x + 4y = 8

Read more about linear equations at

brainly.com/question/4074386

#SPJ1

7 0

1 year ago

Abc + def how many terms and factors

Kipish [7]

This expression has three terms: the variables x, y, and z. We say that the first term is x, that the second term is y, and so on. This expression also has three terms: the number 7, the function f(x), and the variable a.

3 0

3 years ago

If the shaded cross sections of the solids have the same area, which of the following corresponds to the value of a: the side le

Nikolay [14]

Answer:

$4\sqrt{\pi}$

Step-by-step explanation:

The cross section of a sphere is a circle with area $\pi r^2$ , where radius is given as 4
The cross section of the cube is a square with area $a^2$ , where a is side length of square

The circle area = the square area. Thus we have:

$\pi r^2 = a^2 \\\pi(4)^2=a^2\\16\pi=a^2\\\sqrt{16\pi}=a\\ a=\sqrt{16} \sqrt{\pi} \\a=4\sqrt{\pi}$

6 0

3 years ago

Read 2 more answers

The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo

oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

= $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|$

= $=(\frac{1}{2})|-4-6 -8|= 9 units^2$

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

$S_{{\bigtriangleup}ACD'}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2}$ = 10.5 units²

Area of polygon = $S_{{\bigtriangleup}ABCD'}$ = $S_{{\bigtriangleup}ABC}$ + $S_{{\bigtriangleup}ACD'}$ = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0

3 years ago