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2 years ago

Hey guys please help me

Mathematics

1 answer:

Rina8888 [55]2 years ago

8 0

Answer is 20. -4 x 1 is -4 so it doesn’t change. -4 -8 makes it -4 + 8 as there’s two negatives. 9 divided by 3 is 3. So it’s -4 +8 x 3. 8x3 is 24. So -4 + 24 = 20. Therefore final answer is 20

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Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0

4 years ago

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sveta [45]

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3 years ago

Twelve out of 18 students in Mrs. Marlin's class buys pizza for lunch on Fridays.at this rate,if there are 240 students in the e

Bond [772]

I believe it’s 80 but I’m not sure

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3 years ago

In the game of roulette, a player can place a $4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal

creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

$E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}$

$E(x)=\frac{140-148}{38}$

$E(x)=\frac{-8}{38}=-$0.2105$

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

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4 years ago

The graph shows the population of black toads in a forest reserve since their introduction. It also includes functions drawn by

34kurt

Function B best models the researcher's data because it passes through most of the points.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

A graph of best fit can be determined by drawing a straight line or curve on a scatter plot so that the number of points above the line and below the line is about equal and the graph passes through most of the points.

Function B best models the researcher's data because it passes through most of the points.

Find out more on equation at: brainly.com/question/2972832

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2 years ago