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Morgarella [4.7K]
2 years ago
13

Will mark brainliest

Mathematics
1 answer:
Lilit [14]2 years ago
5 0

(2x+1)+(3x-5)=5x-4 you just have to try some of them out and see which ones work

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Write ✓-3 in simplest radical form.
olga nikolaevna [1]

Step-by-step explanation:

In simplest radical form

= √-3

= -3^(1/2)

or

= √-3

= √3i

i is imaginary number, you can write it if you find a negative number in a square root

7 0
2 years ago
Help me please I don’t know how to do it
JulijaS [17]

Answer: The answer is 51

Step-by-step explanation:

4 0
3 years ago
Choose all equivalent expression(s).
ElenaW [278]

<u>Given</u>:

The given expression is a b^{-3 x}

We need to determine the equivalent expression.

<u>Equivalent expression:</u>

Let us determine the equivalent expression.

The equivalent expression can be determined by simplifying the given expression.

Hence, let us apply the exponent rule to simplify the given expression.

Thus, applying the exponent rule, a^{-b}=\frac{1}{a^{b}}, we get;

a(\frac{1}{b^{3x}})

Rewriting the expression, we get;

a(\frac{1^{3x}}{b^{3x}})

Simplifying, we get;

a\left(\frac{1}{b}\right)^{3 x}

Thus, the equivalent expression is a\left(\frac{1}{b}\right)^{3 x}

Hence, Option C is the correct answer.

7 0
3 years ago
Read 2 more answers
(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

4 0
3 years ago
An angle measures 94°. what is the measure of its supplement?
Sliva [168]

Answer:

86

Step-by-step explanation:

180-94

4 0
3 years ago
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