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kolbaska11 [484]
1 year ago
8

Help me pls !! Show with work thankkkk u sooo much !!!!!! :)

Mathematics
1 answer:
postnew [5]1 year ago
6 0
Answer is 12/15 x 5/9 = 4/9

Step by step: first cross cancel to make your numbers to multiply smaller.
I divided 12 and 9 by 3 and 5 and 15 by 5, see attachment.

Then I multiplied across

Answer is 4/9

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Historical data indicates that only 20% of cable customers are willing to switch companies. If a binomial process is assumed, th
Natasha_Volkova [10]

Answer:

a. The probability is 0.735

b. The probability is 0.6296

c. The probability is 0

Step-by-step explanation:

If we assume a binomial process, the probability that x customer are willing to switch companies is:

P(x)=nCx*p^{x}*(1-p)^{n-x}

nCx is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Where n are the 20 cable customers and p is the probability 0.2 that the cable customer are willing to switch companies.

Then, P(x) is:

P(x)=20Cx*0.2^{x}*(1-0.2)^{20-x}

The probability that between 2 and 5 (inclusive) customers are willing to switch companies is:

P(2≤x≤5) = P(2) + P(3) + P(4) + P(5)

Where P(2), P(3), P(4) and P(5) are equal to:

P(2)=20C2*0.2^{2}*(1-0.2)^{20-2}=0.1369

P(3)=20C3*0.2^{3}*(1-0.2)^{20-3}=0.2054

P(4)=20C4*0.2^{4}*(1-0.2)^{20-4}=0.2182

P(5)=20C5*0.2^{5}*(1-0.2)^{20-5}=0.1745

So, P(2≤x≤5) is:

P(2≤x≤5) = 0.1369 + 0.2054 + 0.2182 + 0.1745 = 0.735

At the same way, the probability that less than 5 customers are willing to switch is:

P(x<5)=P(0)+P(1)+P(2)+P(3)+P(4)

P(x<5)=0.6296

Finally, the probability that more than 16 customers are willing to switch is:

P(x>16)=P(17)+P(18)+P(19)+P(20)

P(x>16)=0

7 0
4 years ago
Find three consecutive integers whose sum is -93 and write an equation.
mylen [45]
-30, -31, -32
-30 + -31 + -32 = -93
8 0
3 years ago
What is the approximate value of a local maximum for the polynomial
statuscvo [17]

Answer:

D) 2.5

                                             Aaliyah- ツ

8 0
3 years ago
The dot plot shows the ages of students, in years, on a basketball team.Each dot represents 1 student.Age (yr)nd the mean (round
Sever21 [200]

As given by the question

There are given that the dot plots that show the ages of students.

Now,

As obtained from the dot plot:

x=11,\text{ 11, 11, 12, 12, 12, 13, 13, 13, 13, 14, 14, 15, 15}

Now,

The mean of the given data is:

\text{Mean}=\frac{Addition\text{ of the total given data}}{\text{Total number of data}}

So,

\begin{gathered} \text{Mean}=\frac{Addition\text{ of the total given data}}{\text{Total number of data}} \\ \text{Mean}=\frac{11+11+11+12+12+12+13+13+13+13+14+14+15+15}{14} \end{gathered}

Then,

\begin{gathered} \text{Mean}=\frac{179}{14} \\ \text{Mean}=12.8\text{ years} \end{gathered}

And,

The mode of the given data is:

The mode is defined for the most frequently occurring value

So,

\begin{gathered} \text{Mode}=\text{most frequently occurring value} \\ \text{Mode}=13 \end{gathered}

Hence, the value of the mean is 12.8 and the mode is 13.

4 0
2 years ago
What is greater .5 or .126
levacccp [35]

Answer:

<h2>0.5</h2>

Step-by-step explanation:

0.5 = 0.500

<em>you can add as many as you want 0 after the decimal point. This will not change the value of the number</em>

126 < 500

Therefore

0.126 < 0.500

6 0
4 years ago
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