Hi i a doing the same thing and i have the answer as a hope this helps
<span> Given polynomial x^2+8x-48 = 0</span>
<span>x^2+12x-4x-48 = 0</span>
<span>x(x+12)-4(x+12) = 0</span>
<span>(x+12)(x-4) = 0</span>
<span>x+12 = 0</span>
Subtract 12 from each side.
<span>x+12-12 = 0-12</span>
<span>x = -12</span>
<span>and x-4 = 0</span>
Add 4 to each side.
<span>x-4+4 = 0+4</span>
<span>x = 4</span>
<span>Roots are -12,4.</span>
It takes Owen 2 minutes to eat 1 carrot stick
Answer:
C
Step-by-step explanation:
4(8-x)=8
32-4x=8
-4x=-24
x=6
4x^2 = 12x
4x^2 - 12x = 0
4x(x - 3) = 0
4x = 0
x = 0...not this one
x - 3 = 0
x = 3 <== ur number
