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ch4aika [34]
3 years ago
14

What is the distance between these two points

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

pretty sure it is 11

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What's the answer please, I need help
mezya [45]

Answer:

Ano pong sa Sagutin diyan

Step-by-step explanation:

hindi ko op maintiddihan sorry po

3 0
3 years ago
AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2​
NNADVOKAT [17]

Answer:

Look at Step by step

Step-by-step explanation:

Mean: (a) 1.38

Mean: (b) 1.7

median (a) 1.3

Pacx '?

a]g.;//

>Dc.cccccccccccccccccccccccccccccx;;;;;;;;;;;;;;;;;;;;;;;;;|;z

;zzx';

[c'                  / v\Zcccccccc

8 0
3 years ago
Read 2 more answers
Find a point-slope form for the line with slope 1/5 and passing through the point (- 4. - 8).
andrew11 [14]

Answer:

y+8 = 1/5(x+4)

Step-by-step explanation:

The point slope form of a line is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

y- -8 = 1/5(x - -4)

y+8 = 1/5(x+4)

4 0
3 years ago
Find all solutions for a triangle with A = 40°, B = 60°, and c = 20.
Ket [755]

Answer:C

Step-by-step explanation:

180-(60+40)=80°

C=80°

20/sin80. =a/sin40

a=(20sin40)÷sin80

=13.1

3 0
3 years ago
If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If h(x)=\frac{f(x)}{g(x)}, then:

h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}

Since in our case we want the derivative of h(x) at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}

which, by replacing with the given numerical values:

f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3

becomes:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0

3 0
3 years ago
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