A patient in cardiac arrest presents with pinpoint pupils, track marks, and drug paraphernalia. Of the following,
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Using your knowledge of m/v = g/mL, you can start by putting that in the equation as:
And you know that the volume is 25 mL. So you could put this into the equation as:
And you also know that the molar mass of KCl is 74.55g (K = 39.1 g/mol and Cl = 35.45 g/mol. Add them together to get 74.55g/mol).
We can then put this in the equation as:
Then, we can mulitply them all together:
And now we know that there are 0.01 moles of KCl in the sample.
And you know that the volume is 25 mL. So you could put this into the equation as:
And you also know that the molar mass of KCl is 74.55g (K = 39.1 g/mol and Cl = 35.45 g/mol. Add them together to get 74.55g/mol).
We can then put this in the equation as:
Then, we can mulitply them all together:
And now we know that there are 0.01 moles of KCl in the sample.