Answer:
Molarity of HCl=0.026092M
Explanation:
The equation for the reaction is;
HCl + NaOH ⇒ NaCl + H2O
Using the formular, ..........equ1
where is the concentration of Acid,
is volume of acid
is concentration of the base
is volume of the base
nA is the number of moles of Acid
nB is number of moles of base
nA = 1, nB=1 , ,
,
we will input these values into equation1 to solve for
<u>Answer:</u> 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.
<u>Explanation:</u>
To calculate the moles of silver formed and the moles of excess reagent left after the reaction, we need to balance the equation first and need to find the limiting and excess reagent.
The balanced chemical equation is:
By Stoichiometry:
2 moles of Silver nitrate reacts with 1 mole of Zinc metal
So, 6.5 moles of silver nitrate will react with = of zinc metal
The required amount of zinc metal is less than the given amount of zinc metal, hence, it is considered as an excess reagent.
Therefore, silver nitrate is the limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of silver nitrate produces 2 moles of silver metal
So, 6.5 moles of silver nitrate will produce = of silver metal.
Number of moles of excess reagent left after the completion of reaction = (3.8 - 3.25)moles = 0.55 moles
Hence, 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.
The concentrations : 0.15 M
pH=11.21
<h3>Further explanation</h3>The ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15