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1 year ago

Which instrument below is used to measure an intensive property?

Chemistry

1 answer:

Andrei [34K]1 year ago

4 0

An intensive property is the physical characteristics that have an independent magnitude. The thermometer can be used to measure the temperature. Thus, option C is correct.

<h3>What is an intensive property?</h3>

An intensive property has been constituted of the parameters that are not dependent on the size and the mass of the sample. Density, pressure, and temperature are some intensive properties.

The first image shows a weighing balance, the second shows a volumetric cylinder, and the fourth shows a ruler used to measure mass, volume, and length respectively, which are extensive properties.

Therefore, option C. thermometer measures temperature, which is an intensive property.

Learn more about the intensive property here:

brainly.com/question/17323212

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3 years ago

How can the rate constant be determined from the rate law?

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2 years ago

I need part 1 and 2 please , just separate answers

Vladimir79 [104]

First, we have to remember the molarity formula:

$M=\text{ }\frac{moles\text{ of solute}}{L\text{ solution}}$

Part 1:

In this case, our solute is sodium nitrate (NaNO3), and we have the mass dissolved in water, then we have to convert grams to moles. For that, we need the molecular weight:

$M.W_{NaNO_3}=\text{ 23+14+16*3= 85 g/mol}$

Then, we calculate the moles present in the solution:

$3.976\text{ g NaNO}_3\text{ * }\frac{1\text{ mol}}{85\text{ g}}=\text{ 0.04678 mol NaNO}_3$

Now, we have the necessary data to calculate the molarity (with the solution volume of 200 mL):

$M=\frac{0.04678\text{ mol}}{200\text{ mL*}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.2339 M}$

The molarity of this solution equals 0.2339 M.

Part 2:

In this case, we have the same amount (in moles and mass) of sodium nitrate, but a different volume of solution, then we only have to change it:

$M=\text{ }\frac{0.04678\text{ mol}}{275\text{ mL *}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.1701 M}$

So, the molarity of this solution is 0.1701 M.

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8 months ago