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Novosadov [1.4K]
3 years ago
14

Describe and correct the error in finding DC

Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

DC = 2

Step-by-step explanation:

The wrong equation was used.

The right equation to use based on the midsegment theorem of a trapezoid is:

MN = ½(AB + DC)

MN = 8

AB = 14

Substitute

8 = ½(14 + DC)

Multiply both sides by 2

8*2 = ½(14 + DC)*2

2*8 = 14 + DC

16 = 14 + DC

16 - 14 = 14 + DC - 14

2 = DC

DC = 2

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7-ounce package costs $2.59. A 12 ounce package costs $4.56. An 18 ounce package costs $6.30. Which package is the best buy?
Yanka [14]

Answer:

18 ounce package for $6.30

Step-by-step explanation:

For each one, you divide the money by the package to see how much it is per ounce.

2.59 / 7 = $0.37 per oz

4.56 / 12 = $0.38 per oz

6.30 / 18 = $0.35 per oz

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What is the area of a circle with a radius of 21 feet?
lidiya [134]

Answer:

Area is about 1520.53

Step-by-step explanation:

A=\pi r^{2}

A = \pi 21^{2}

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6 0
3 years ago
A survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10. (a)
skad [1K]

Answer:

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

<u>Step-by-step explanation</u>:

Step:-(i)

Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10

The sample size 'n' = 25

The mean of the sample   x⁻  = $28

The standard deviation of the sample (S) = $10.

Level of significance ∝=0.05

The degrees of freedom γ =n-1 =25-1=24

tabulated value t₀.₀₅ = 2.064

<u>Step 2:-</u>

The 95% of confidence intervals for the average spending

((x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )

(28 - 2.064 \frac{10}{\sqrt{25} } ,28 + 2.064\frac{10}{\sqrt{25} } )

( 28 - 4.128 , 28 + 4.128)

(23.872 , 32.128)

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b)

Null hypothesis: H₀:μ<30

Alternative Hypothesis: H₁: μ>30

level of significance ∝ = 0.05

The test statistic

t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

t = \frac{28-30 }{\frac{10}{\sqrt{25} } }

t = |-1|

The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

<u>Conclusion</u>:-

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

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What problem do you set up to find x and y
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