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3 years ago

5

a rectangular garden has a perimeter of 54 feet. it's length is 3 less than twice its width. write and solve an equation to solv

e for the gardens dimensions

1 answer:

Yanka [14]3 years ago

5 0

2(L+W)=54
L=2W-3
Substitute L in the first equation:
2((2W-3)+W)=54.
Divide by 2:
(2W-3)+W=27
Simplify by collecting like terms:
3W-3=27.
Add 3:
3W=30.
Divide by 3 to get that
W=10.
Substitute the L and W relations to get
L=2W-3
L=2*10-3
L=17.
The answers are length is 17 and width is 10.

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$y_{o}$ - Initial y-position, in meters.

$v_{o,y}$ - Initial y-velocity, in meters per second.

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If we know that $y_{o} = 0\,m$ , $v_{o,y} = -3.6\,\frac{m}{s}$ , $t = 0.60\,s$ and $a_{y} = 0\,\frac{m}{s^{2}}$ , then the x-position of the skateboarder is:

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