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3 years ago

If a car was traveling at a speed of 30km/hr. How far did the car travel in 3 hours? *

Physics

1 answer:

harina [27]3 years ago

8 0

Answer:

The answer is

Explanation:

To find the distance covered by an object given it's velocity and time taken , we use the formula

<h3>distance = velocity × time</h3>

From the question

velocity = 30 km/hr

time = 3 hrs

The distance covered is

distance = 30 × 3

We have the final answer as

Hope this helps you

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The headwater of three different river systems are also found in Wyoming. Identify these three river systems.

S_A_V [24]

Answer:

The Wind Missouri-Mississippi, The Snake Columbia, and the Green-Colorado drainage.

Explanation:

The wind river ranges of the Wyoming is a major headwaters system of the united states and the rage is home to about 63 glaciers and ten of the largest glacier of the united states are found in this region. The wind river range is about 77% of the area s located in the drainage.

The green river is located in the western united states and forms a green river basin of about 730 miles long and covers much of the Colorado plateaus and the snake river forms in a major area of the Sierra Nevada and the cascade range.

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3 years ago

Which law describes how the Earth applies a gravitational force on the Moon, the Moon applies a gravitational force on Earth? *

nikdorinn [45]

The answer is Newton's 3rd Law. The reason why is because a force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject ofNewton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.

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3 years ago

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A clothes dryer uses about 30 amps of current from a 240 volt line. How much power does it use?

Aneli [31]

Not sure if this answer is write or wrong but i think its <span>4500 watts

</span>

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3 years ago

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A fillet weld has a cross-sectional area of 25.0 mm2and is 300 mm long. (a) What quantity of heat (in joules) is required to acc

HACTEHA [7]

Answer:

77362.56 J

163730.28571 J

Explanation:

A = Area = 25 mm²

l = Length = 300 mm

K = Constant = $3.33\times 10^{-6}$

$\eta$ = Heat transfer factor = 0.75

$f_m$ = Melting factor = 0.63

T = Melting point of low carbon steel = 1760 K

Volume of the fillet would be

$V=Al\\\Rightarrow V=25\times 300\\\Rightarrow V=7500\ mm^3=7500\times 10^{-9}\ m^3$

The unit energy for melting is given by

$U_m=KT^2\\\Rightarrow U_m=3.33\times 10^{-6}\times 1760^2\\\Rightarrow U_m=10.315008\ J/mm^3$

Heat would be

$Q=U_mV\\\Rightarrow Q=10.315008\times 7500\\\Rightarrow Q=77362.56\ J$

Heat required to weld is 77362.56 J

Amount of heat generation is given by

$Q_g=\dfrac{Q}{\eta f_m}\\\Rightarrow Q_g=\dfrac{77362.56}{0.75\times 0.63}\\\Rightarrow Q_g=163730.28571\ J$

The heat generated at the welding source is 163730.28571 J

7 0

4 years ago

A uniform cylinder of radius 10 cm and mass 20 kg is mounted so as to rotate freely about a horizontal axis that is parallel to

fomenos

Answer:

a. 0.15 kg m2

b. 19.8 rad/s

Explanation:

Metric unit conversion:

10 cm = 0.1 m

5 cm = 0.05 m

a. Using parallel axis theorem, the rotational inertia of the cylinder about the axis of rotation is the inertia about the longitudinal axis plus the product of mass and distance from the longitudinal axis to the rotational axis squared

$I = I_L + md^2$

whereas the inertia about the longitudinal axis of the solid cylinder is

$I_L = mr^2/2 = 20*0.1^2/2 = 0.1 kgm^2$

$md^2 = 20*0.05^2 = 0.05 kgm^2$

$I = I_L + md^2 = 0.1 + 0.05 = 0.15 kg m^2$

b. Assume the cylinder does not rotate about its own longitudinal axis, we can treat this as a point mass pendulum. So when it's being released from 0.05m high (release point) to 0m (lowest position), its potential energy is converted to kinetic energy:

$E_p = E_k$

$mgh = mv^2/2$

where h = 0.05 is the vertical distance traveled, v is the cylinder linear velocity at the lowest position.g = 9.81m/s2 is the gravitational acceleration.

We can divide both sides by m

$gh = v^2/2$

$v^2 = 2gh = 2*9.81*0.05 = 0.981$

$v = \sqrt{0.981} = 0.99 m/s$

The angular speed is linear speed divided by the radius of rotation, which is distance from the cylinder center to the center of rotation d = 0.05 m

$\omega = \frac{v}{d} = \frac{0.99}{0.05} = 19.8 rad/s$

5 0

3 years ago