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Alexeev081 [22]
3 years ago
12

the function FX Has a slope of negative 2 & a y-intercept of two what is the slope of it in the y intercept

Mathematics
1 answer:
Pavel [41]3 years ago
5 0
Idk the answer sorry.
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A rectangle has a length of (5x+2) and a width of (3x-1) with an area of 308 square units. Find the perimeter
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7 0
3 years ago
What is 1,000 to the power of 4?
quester [9]
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8 0
3 years ago
Determine the domain and range of the graph.
nirvana33 [79]

Answer:

Domain [-4,4]

Range [-2,2]

Step-by-step explanation:

The domain is the x-values of the graph and the range in the y-values. When writing domain and range it should be from least to greatest. So to find the domain find the lowest x-value on the graph and then the highest. Next, do the same for y-values. Finally, either surround each value with parentheses or bracket, the difference is that brackets mean that value is included, while parentheses mean that value is not actually on the graph.

In this case, the lowest x-value is -4 and the highest is 4, both values are included as signified by the closed circles, therefore the domain is [-4,4]. The lowest y value is -2 and the highest is 2, both are included, therefore the range is [-2,2].

4 0
3 years ago
1.13 Thank you! (Sorry it’s so blurry)
VikaD [51]
\sqrt[8]{48^4}  can be rewritten as 48^4 to the \frac{1}{8}  power:

(48^4)^ \frac{1}{8}

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

(48^ \frac{1}{2})

This is equivalent to \sqrt{48}, so now, we just simplify:

\sqrt{48}=  \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}

So:

\sqrt[8]{48^4} =4 \sqrt{3} 


4 0
3 years ago
What's blah+blah=? jvghdskcghsdjfgbkaehfeklgabkregbfjkabkjdsbfkjbdsfkjb,adgjk
Dimas [21]

blah + blah = blah blah

hope it helps!

7 0
2 years ago
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