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mestny [16]
3 years ago
9

An artist can sell 20 copies of a painting at $100 each, but for each additional copy he makes, the value of each painting will

go down by a dollar. Thus, if 22 copies are made, each will sell for $98. How many copies should he make to maximize his sales?
Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

40 more paintings in order to maximize sales making a total of 60 paintings

Step-by-step explanation:

Let x= no.of copies above 20

Total Sales(x) = (number of copies)(price per copy)

Sales (x)= (20 +x)(100 –x)

Open bracket

=1200-20x+100x-x^2

=1200+80x-x^2

Derivative of the sales

80-2x=0

80=2x

Divide both sides by 2

40=x

Because Sales(x)= –2, this is maximal by the second derivative test

The artist should make 40 more paintings in order to maximize sales making a total of 60 paintings.

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Answer:

The area of the rectangular playroom is 260 feet² .

Step-by-step explanation:

Given:

The perimeter of the rectangular playroom is 72 feet and it's width is 10 feet.

Now, to find its area we need the length .

So, putting the formula of perimeter we get it's length:

Let the length be l .

Perimeter = 2( length + width)

72=2(l+10)

72=2l+20

subtracting both sides from 20:

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52=2l

Dividing both sides by 2:

52\div2=2l\div2

26=l

Length is 26 feet.

And, to get the area we put the formula of finding the area:

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Area=26\times 10

Area=260

Therefore, the area of the rectangular playroom is 260 feet² .

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Step-by-step explanation:

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