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Cerrena [4.2K]
1 year ago
12

Which of these electron transitions correspond to absorption of energy and which to emission?

Chemistry
1 answer:
Monica [59]1 year ago
3 0

The energy will be absorbed for the electron transitions n= 3 to n= 4.

There are two ways in which electrons can transition between energy levels:

  1. Absorption spectra: This type of spectra is seen when an electron jumps from a lower energy level to a higher energy level. In this process, energy is absorbed.
  2. Emission spectra: This type of spectra is seen when an electron jumps from a higher energy level to a lower energy level. In this process, energy is released in the form of photons.

for n=3 to n=4,  the equation used to calculate the energy of transition is,

E = - 2.178×10⁻¹⁸J ( 1 / ni² - 1/nf ²)

Thus, for n = 3 to n = 4, as the electron is getting jumped from lower energy level (n = 3) to higher energy level (n = 4), the energy will be absorbed.

For more information about absorption visit the link:

brainly.com/question/14649237?referrer=searchResults

#SPJ4

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How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 46.0 mL of 0.584 M CuSO4
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<h3>Answer:</h3>

2.624 g

<h3>Explanation:</h3>

The equation for the reaction is given as;

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  • Volume of CuSO₄ as 46.0 mL;
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We are required to calculate the mass of Cu(OH)₂ precipitated

  • We are going to use the following steps;
<h3>Step 1: Calculate the number of moles of CuSO₄ used</h3>

Molarity = Number of moles ÷ Volume

To get the number of moles;

Moles = Molarity × volume

          = 0.584 M × 0.046 L

          = 0.0269 moles

<h3>Step 2: Calculate the number of moles of Cu(OH)₂ produced </h3>
  • From the equation 1 mole of CuSO₄ reacts to give out 1 mole of Cu(OH)₂
  • Therefore; Mole ratio of CuSO₄ to Cu(OH)₂ is 1 : 1.

Thus, Moles of CuSO₄ = Moles of Cu(OH)₂

Hence, moles of Cu(OH)₂ = 0.0269 moles

<h3>Step 3: Calculate the mass of Cu(OH)₂</h3>

To get mass we multiply the number of moles with the molar mass.

Mass = Moles × Molar mass

Molar mass of Cu(OH)₂ is 97.561 g/mol

Therefore;

Mass of Cu(OH)₂ = 0.0269 moles × 97.561 g/mol

                           = 2.624 g

Thus, the mass of Cu(OH)₂ that will precipitate is 2.624 g

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