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Oliga [24]
3 years ago
8

What must happen for liquid water to become water vapor? Select one: A. The water molecules must lose energy and stop moving. B.

The water molecules must exert less pressure on their container. C. The water molecules must gain kinetic energy. D. The water molecules must lose heat and gain volume.
Chemistry
1 answer:
kirill [66]3 years ago
3 0
When water turns from a liquid into a vapor, the molecules actually spread out and move farther apart.

We can actually use a process of elimination here, to take out the answers that couldn't be correct.

The molecules don't become smaller, because when water turns from a liquid to a vapor, it goes through a physical change, not a chemical change.

The molecules don't become heavier. Water vapor is lighter and less dense than liquid water.

The molecules don't increase in number either. Because we know that molecules can't just appear out of nowhere. There really is no form of matter that can just appear out of nowhere
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George Washington Carver received _____ from God during early morning walks in the woods.?
BabaBlast [244]

Answer:

1. Guidance

2. Inspiration

I think this is right hope it helps

8 0
4 years ago
CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7
padilas [110]

<u>Answer:</u> The \Delta G for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)

We are given:

\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol

To calculate \Delta G^o_{rxn} for the reaction, we use the equation:

\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]

For the given equation:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J

Conversion factor used = 1 kJ = 1000 J

The expression of K_p for the given reaction:

K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}

We are given:

p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm

Putting values in above equation, we get:

K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85

To calculate the gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol

Hence, the \Delta G for the reaction is 54.425 kJ/mol

7 0
3 years ago
Ann dissolves four tablespoons of salt in a bowl of water. She notices that the water has become salty. Ann then keeps
antoniya [11.8K]

Answer:

2)Both the salt dissolving and the evaporation of water are physical changes.

Explanation:

The two kinds of changes that has occurred are both physical changes.

Dissolution of a solute such as salt in water and evaporation of water from a solution are physical changes.

A physical change is one in which the physical property of matter is altered. Particularly the state and the form.

In many of these cases, the change is easily reversible.

Since this change is reversible in that we were able to collect the salt back, this is a physical change.

6 0
3 years ago
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Tems11 [23]
Answer : Eight electrons
6 0
3 years ago
Determine the hydroxide ion concentration in<br> a solution that is 0.028 M NaOH.
Savatey [412]
Answer = 0.0007 moldm
7 0
4 years ago
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