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2 years ago

Add.

Mathematics

2 answers:

Elina [12.6K]2 years ago

8 0

Answer:

2x²+4x-4

Step-by-step explanation:

hope this helps,

that's how you can add, check out the image i uploaded

maxonik [38]2 years ago

8 0

**Disclaimer** Hi there! I assumed the [ x- ] part is not included in the question. The following answer is according to this understanding. Please let me know if it is incorrect and I will modify my answer correspondingly.

Answer: $C.~\Large\boxed{2x^2+4x-4}$

Step-by-step explanation:

Given expression

$(2x^2-2x)+(6x-4)$

Expand the parenthesis

$2x^2-2x+6x-4$

Combine like terms

$\Large\boxed{2x^2+4x-4}$

Hope this helps!! :)

Please let me know if you have any questions

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Click here What is the average rate of change for this exponential function for the interval from x=2 to x = 4? 15 10 -5 5 10 O

Triss [41]

Answer:

c. 6

Step-by-step explanation:

Given

See attachment for graph

Required

Average rate of change

This is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

Where

$(a,b) = (2,4)$

So, we have:

$Rate = \frac{f(4) - f(2)}{4 - 2}$

$Rate = \frac{f(4) - f(2)}{2}$

Using the attached graph, we have:

$f(2) = 4$

$f(4) = 16$

So, we have:

$Rate = \frac{16- 4}{2}$

$Rate = \frac{12}{2}$

$Rate = 6$

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3 years ago

Evaluate 8^2/3 using the power to a power rule (a^x)^y = a^xy

saveliy_v [14]

Answer:

Step-by-step explanation:

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3 years ago

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Mashutka [201]

Answer:

1) Product of 2 x 3/5 is 6/5 or 1 and 1/5.

2) 20/9 or 2 and 2/9

3) 15/8 or 1 and 7/8

4) 15/6 or 2 and 3/6 or 2 and 1/2

5) 6/4 or 1 and 2/4 or 1 and 1/2

Step-by-step explanation:

You multiply the whole number by the numerator (top number) and then divide the result by the denominator(bottom number). Afterward, simplify the fraction if you can, for example, 6/9. Both the numerator and denominator can be divided by 3. Therefore, the answer to that example is 2/3.

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3 years ago

Read 2 more answers

Instant Oats cost $4.89 for 10 servings. What is the cost per 1 serving

tester [92]

Look at the attached picture⤴

Hope it will help u...