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nikitadnepr [17]
2 years ago
7

Add.

Mathematics
2 answers:
Elina [12.6K]2 years ago
8 0

Answer:

2x²+4x-4

Step-by-step explanation:

hope this helps,

that's how you can add, check out the image i uploaded

maxonik [38]2 years ago
8 0

<em>**Disclaimer** Hi there! I assumed the [ x- ] part is not included in the question. The following answer is according to this understanding. Please let me know if it is incorrect and I will modify my answer correspondingly.</em>

Answer: C.~\Large\boxed{2x^2+4x-4}

Step-by-step explanation:

<u>Given expression</u>

(2x^2-2x)+(6x-4)

<u>Expand the parenthesis</u>

2x^2-2x+6x-4

<u>Combine like terms</u>

\Large\boxed{2x^2+4x-4}

Hope this helps!! :)

Please let me know if you have any questions

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Annual salary plus bonus data for chief executive officers are presented in the BusinessWeek Annual Pay Survey. A preliminary sa
Anuta_ua [19.1K]

Answer:

175

Step-by-step explanation:

The sample size n in<em> Simple Random Sampling</em> is given by

\bf n=\frac{z^2s^2}{e^2}

<em> where z = 1.96 is the z-score associated with a 95% confidence level ans s the standard deviation. </em>

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3 years ago
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Answer:

The volume is:

\displaystyle\frac{37\pi}{10}

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

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So the integral becomes:

\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx

We solve it:

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\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx

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\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx

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Simplifying a bit:

\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4

Then plugging the limits of the integral:

\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]

Taking the root (rational exponents):

\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]

Then doing those arithmetic computations we get:

\displaystyle\frac{37\pi}{10}

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