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crimeas [40]
3 years ago
14

A dilation with a scale factor of 2 is applied to the three line segments shown. The resulting images are P′Q′¯¯¯¯¯¯¯, A′B′¯¯¯¯¯

¯¯, and M′N′¯¯¯¯¯¯¯¯¯.
What are the lengths of the images?
Drag the answer into the box to match each segment.

Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer:

Step-by-step explanation:

Formula to determine the scale factor,

Scale factor = \frac{\text{Dimension of the image}}{\text{Dimension of the original}}

2 = \frac{P'Q'}{PQ}

2 = \frac{P'Q'}{2}

P'Q' = 4 cm

Similarly, for the length of A'B',

2 = \frac{A'B'}{AB}

2 = \frac{A'B'}{1.5}

A'B' = 3 cm

For the length of M'N',

2 = \frac{M'N'}{MN}

2 = \frac{M'N'}{3}

M'N' = 6 cm

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Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

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Let P(R) represent the probablity of picking a red marble,

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\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

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\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

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