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crimeas [40]
3 years ago
14

A dilation with a scale factor of 2 is applied to the three line segments shown. The resulting images are P′Q′¯¯¯¯¯¯¯, A′B′¯¯¯¯¯

¯¯, and M′N′¯¯¯¯¯¯¯¯¯.
What are the lengths of the images?
Drag the answer into the box to match each segment.

Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer:

Step-by-step explanation:

Formula to determine the scale factor,

Scale factor = \frac{\text{Dimension of the image}}{\text{Dimension of the original}}

2 = \frac{P'Q'}{PQ}

2 = \frac{P'Q'}{2}

P'Q' = 4 cm

Similarly, for the length of A'B',

2 = \frac{A'B'}{AB}

2 = \frac{A'B'}{1.5}

A'B' = 3 cm

For the length of M'N',

2 = \frac{M'N'}{MN}

2 = \frac{M'N'}{3}

M'N' = 6 cm

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What is the equation of the line that passes through (-2, 2) and (1, -4)?
poizon [28]

Answer:

y = - 2x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁  = (- 2, 2) and (x₂, y₂ ) = (1, - 4)

m = \frac{-4-2}{1+2} = \frac{-6}{3} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, 2), then

2 = 4 + c ⇒ c = 2 - 4 = - 2

y = - 2x - 2 ← equation of line

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3 years ago
Find the value of sin T rounded to the nearest hundredth, if necessary.
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<h3>Answer:  0.6</h3>

========================================

Work Shown:

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6 0
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3 years ago
Out of 450 applicants for a job, 206 are male and 62 are male and have a graduate degree.
xxMikexx [17]

Answer:

0.3009 is the  probability that the applicant has graduate degree given he is a male.                                                              

Step-by-step explanation:

We are given he following in the question:

M: Applicant is male.

G: Applicant have a graduate degree

Total number of applicants = 450

Number of male applicants = 206

n(M) = 206

Number of applicants that are male and have a graduate degree = 62

n(M\cap G) = 62

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(M) = \dfrac{206}{450} = 0.4578

P(M\cap G) = \dfrac{n(M\cap G)}{n} = \dfrac{62}{450} = 0.1378

We have to find the probability that the applicant has graduate degree given he is a male.

P(G|M) = \dfrac{P(G\cap M)}{P(M)} = \dfrac{\frac{62}{450}}{\frac{206}{450}} = \dfrac{62}{206} = 0.3009

Thus, 0.3009 is the  probability that the applicant has graduate degree given he is a male.

5 0
3 years ago
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