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Answer 1

The Graph is not linear.

To graph f, we graph the equation y = f(x). To this end, we use the techniques outlined in Section 1.2.1. Specifically, we check for intercepts, test for symmetry, and plot additional points as needed. To find the x-intercepts, we set y = 0. Since y = f(x), this means f(x) = 0. f(x) = x2−x−6 0 = x2−x−6 0 = (x−3)(x+2) factor x−3=0 or x+2=0 x = −2,3 So we get (−2,0) and (3,0) as x-intercepts. To find the y-intercept, we set x = 0. Using function notation, this is the same as finding f(0) and f(0) = 02 − 0 − 6 = −6. Thus the y-intercept is (0, −6). As far as symmetry is concerned, we can tell from the intercepts that the graph possesses none of the three symmetries discussed thus far. (You should verify this.) We can make a table analogous to the ones we made in Section 1.2.1, plot the points and connect the dots in a somewhat pleasing fashion to get the graph below on the right. y x f(x) (x, f(x)) −3 6 (−3,6) −2 0 (−2,0) −1 −4 (−1,−4) 0 −6 (0, −6) 1 2 3 4 5 6 7 −3−2−11 2 3 4 1 −6 (1, −6) 2 −4 (2, −4) 3 0 (3, 0) 4 6 (4, 6)

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