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yan [13]
2 years ago
10

Solid iodine trichloride is prepared in two steps: first, a reaction between solid iodine and gaseous chlorine to form solid iod

ine monochloride; then, treatment with more chlorine.
(c) How many grams of iodine are needed to prepare 2.45 kg of final product?
Chemistry
1 answer:
babymother [125]2 years ago
4 0

In order of increasing intermolecular force strength, solid iodine, liquid bromine, and chlorine gas should be ranked as follows: solid iodine, liquid bromine, and chlorine gas.

<h3>What is bromine?</h3>

The chemical element bromine has the atomic number 35 and the symbol Br. It is the third-lightest halogen, and at room temperature,It is a flammable reddish-brown liquid that quickly turns into a corresponding color vapour when it evaporates. Its properties are halfway between those of chlorine and iodine. It was discovered separately by two chemists, Carl Jacob Löwig (1825) and Antoine Jérôme Balard (1826), and was given the name o (meaning "stench") to reflect its noxious odor.

To learn more about bromine from the given link:

brainly.com/question/1952132

#SPJ4

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A prairie dog runs into its burrow as a coyote approaches.This behavior helps the prairie dog
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This behavior helps the prairie dog from being prey upon by coyote.
Prairie dogs live in burrow and they normally do not move much away from their burrows. When they sense danger they will dash quickly back into their burrows. This behavioral adaptation protect them from predators.
4 0
4 years ago
The final marks in a statistics course are normally distributed with a mean of 70 and a standard deviation of 10. The professor
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Use inversenormal on a calculator and type in .1 , 70 , 10 . That percent is for A and will determine at what mark an A will be. Do the same for the rest of the grades but change the first argument in the calculation
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3 years ago
10 points
Morgarella [4.7K]
I think it’s 1 Carbon, 4 hydrogens.
7 0
3 years ago
How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
tino4ka555 [31]

Taking into account the reaction stoichiometry, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CO₂ + 4 H₄  → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CO₂: 1 mole
  • H₄: 4 moles  
  • CH₄: 1 mole
  • H₂O: 2 moles

<h3>Moles of CH₄ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}

<u><em>moles of CH₄= 340.4 moles</em></u>

Then, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

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6 0
2 years ago
50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximat
trapecia [35]

Answer:

4.76

Explanation:

In this case, we have to start with the <u>buffer system</u>:

CH_3COOH~->~CH_3COO^-~+~H^+

We have an acid (CH_3COOH) and a base (CH_3COO^-). Therefore we can write the <u>henderson-hasselbach reaction</u>:

pH~=~pKa+Log\frac{[CH_3COO^-]}{[CH_3COOH]}

If we want to calculate the pH, we have to <u>calculate the pKa</u>:

pH=-Log~Ka=4.76

According to the problem, we have the <u>same concentration</u> for the acid and the base 0.1M. Therefore:

[CH_3COO^-]=[CH_3COOH]

If we divide:

\frac{[CH_3COO^-]}{[CH_3COOH]}~=~1

If we do the Log of 1:

Log~1=~zero

So:

pH~=~pKa

With this in mind, the pH is 4.76.

I hope it helps!

8 0
3 years ago
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