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nikklg [1K]
3 years ago
5

Carbon monoxide and chlorine combine in an equilibrium reaction to produce the highly toxic product, phosgene (COCl2 ) CO(g) Cl2

(g) COCl2 (g) If the equilibrium constant for this reaction is Kc = 248, predict, if possible, what will happen when the reactants and product are combined with the concentrations shown. [CO] = [Cl2] = 0.010 M; [COCl2] = 0.070 M
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

Reaction will proceed towards forward direction.

Explanation:

Balanced reaction: CO+Cl_{2}\rightleftharpoons COCl_{2}

Reaction quotient (Q_{c}) for this reaction is represented as:

                                         Q_{c}=\frac{[COCl_{2}]}{[CO][Cl_{2}]}

Here, [CO] = [Cl_{2}] = 0.010 M and [COCl_{2}] = 0.070 M

                              So, Q_{c}=\frac{0.070}{(0.010)^{2}} = 700

As Q_{c} > K_{c} therefore reaction will proceed towards forward direction i.e. moreCOCl_{2} will be produced.

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How many moles of iron(III) hydroxide precipitate will form when 2.7 moles of aqueous sodium hydroxide reacts completely with ex
aalyn [17]

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0.9 mole of Fe(OH)3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

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7 0
3 years ago
During a laboratory experiment, 9.68 g of iron reacted with excess sulfur to form 13.8 grams of iron II sulfide. Calculate the p
Daniel [21]

Answer:

Percent yield = 90.8%

Explanation:

The reaction of Fe with S to produce FeS is:

Fe + S → FeS

<em>Where the moles of Fe added in excess of S are the moles of FeS</em>

<em />

Now, percent yield is defined as 100 times the ratio between actual yield (13.8g of FeS) and theoretical yield (15.2g FeS):

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5 0
3 years ago
If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.
AVprozaik [17]
Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
------------------------------------------------------------------------------------------------------
Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is [OH-] = 1 * 10^{-13} mol/L

Hope this helps!
3 0
4 years ago
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