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nikklg [1K]
3 years ago
5

Carbon monoxide and chlorine combine in an equilibrium reaction to produce the highly toxic product, phosgene (COCl2 ) CO(g) Cl2

(g) COCl2 (g) If the equilibrium constant for this reaction is Kc = 248, predict, if possible, what will happen when the reactants and product are combined with the concentrations shown. [CO] = [Cl2] = 0.010 M; [COCl2] = 0.070 M
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

Reaction will proceed towards forward direction.

Explanation:

Balanced reaction: CO+Cl_{2}\rightleftharpoons COCl_{2}

Reaction quotient (Q_{c}) for this reaction is represented as:

                                         Q_{c}=\frac{[COCl_{2}]}{[CO][Cl_{2}]}

Here, [CO] = [Cl_{2}] = 0.010 M and [COCl_{2}] = 0.070 M

                              So, Q_{c}=\frac{0.070}{(0.010)^{2}} = 700

As Q_{c} > K_{c} therefore reaction will proceed towards forward direction i.e. moreCOCl_{2} will be produced.

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Answer:

1. Exponential growth

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Answer:

3. Innate behavior

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8 0
3 years ago
Electromagnetic forces are the predominant force in holding what subatomic particles together?
vova2212 [387]
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4 0
3 years ago
You are requested to reduce the size of 50 ton/hr of a given solid. The size of the feed is such 80% passes a 4-in (76.2 mm) scr
defon

Answer:

1) The power needed to process 50 ton/hr is 135.4 HP.

2) The void fraction of the bed is 0.37.

Explanation:

1) For this type of milling operations, we can estimate the power needed for an operation according to the work index (Ei), the passing size of the circuit feed (F80) and the passing size of the product (P80).

We assume the units of Ei are kWh/t.

The equation that relates this parameters and the power is (size of particles in μm):

W=Ei*(\frac{10}{\sqrt{P80}} -\frac{10}{\sqrt{F80}} )\\\\W=9.45*(\frac{10}{\sqrt{3175\mu m}} -\frac{10}{\sqrt{76200mm}} )\\\\\\W=9.45*(0.1774+0.0362)=2.019 kWh/t

The power needed to process 50 ton/hor is

P=2.0194\frac{kWh}{Ton}*\frac{50Ton}{h}*\frac{1.341HP}{1kW}=   135.4 \, HP

2) The density of the packed bed can be expressed as

\rho=f_v*\rho_v+f_s*\rho_s

being f the fraction and ρ the density of every fraction. We know that the density of the void is 0 (ρv=0) and that fv=1-fs (the sum  of the fractions ois equal to the total space).

Then we can rearrange

\rho=f_v*\rho_v+f_s*\rho_s\\\\\rho=f_v*0+(1-f_v)*\rho_s\\\\\rho/\rho_s=1-f_v\\\\f_v=1-\rho/\rho_s=1-990/1570=1-0.63=0.37

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6 0
3 years ago
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The two observations you would make about the atoms are

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Answer:

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