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Dima020 [189]
2 years ago
15

What is the volume in milliliter of 7.44 g of acetone

Chemistry
1 answer:
Mademuasel [1]2 years ago
7 0

The correct answer is 9.4897 mL

It is necessary to understand a substance's mass, volume, and density in order to answer this question. By dividing a material's mass by volume, the density of the substance may be calculated. The equation for density may now be written in mathematical form using the expression for density, and the equation for mass can be produced by rearrangement using the equation for density as a starting point.

Mass of acetone = 7.44 g (given)

Volume of acetone (v) =  mass of acetone ÷ density of acetone

V = 7.44 g ÷ 0.784 g/mL

V = 9.4897 mL

Hence volume of acetone = 9.4897 mL

To learn more about density refer the link:

brainly.com/question/6107689

#SPJ9

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Which of the changes of state shown in the model happen when thermal energy is added
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Answer:

sublimation

Explanation:

immediately into a gas when thermal energy is added to it. The process is called sublimation. Sublimation is the change of state from a solid to a gas without going through the liquid state.

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3 years ago
which of the following experiments follow ethical standards? A.)performing test on animals when the information can be obtained
olasank [31]
The answer is D because it sounds like the most ethical answer. The other choices are wrong because the could possibly hurt someone or an animal.
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Una de las maneras de eliminar el NO en las emisiones de humo es hacerle reaccionar con amoniaco
inna [77]

Answer:

Spanish I dont know spanish.

Explanation:

7 0
3 years ago
Calculate the mass of ethyl alcohol required to prepare 540 grams of C4H6, if the reaction follows the scheme:
kkurt [141]

Answer:

Explanation:

2C₂H₅OH    =   C₄H₆  +  2H₂O  +  H₂

2 mole               1 mole

molecular weight of ethyl alcohol

mol weight of C₂H₅OH = 46 gm            

mol weight of C₄H₆  54 gm

540 gm of C₄H₆ = 10 mole

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3 0
3 years ago
If the initial temperature of a movable cylinder was 50 degrees Celsius
slega [8]

Answer:

8.45 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 50 °C

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 0 °C

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 50 °C

Initial temperature (T₁) = 50 °C + 273

Initial temperature (T₁) = 323 K

Final temperature (T₂) = 0 °C

Final temperature (T₂) = 0 °C + 273

Final temperature (T₂) = 273 K

Finally, we shall determine the new volume. This can be obtained as follow:

Initial temperature (T₁) = 323 K

Initial pressure (P₁) = 2 atm

Initial volume (V₁) = 5 L

Final temperature (T₂) = 273 k

Final pressure (P₂) = 1 atm

Final volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

2 × 5 / 323 = 1 × V₂ / 273

10 / 323 = V₂ / 273

Cross multiply

323 × V₂ = 10 × 273

323 × V₂ = 2730

Divide both side by 323

V₂ = 2730 / 323

V₂ = 8.45 L

Thus, the new volume is 8.45 L

5 0
3 years ago
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