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Dima020 [189]
2 years ago
15

What is the volume in milliliter of 7.44 g of acetone

Chemistry
1 answer:
Mademuasel [1]2 years ago
7 0

The correct answer is 9.4897 mL

It is necessary to understand a substance's mass, volume, and density in order to answer this question. By dividing a material's mass by volume, the density of the substance may be calculated. The equation for density may now be written in mathematical form using the expression for density, and the equation for mass can be produced by rearrangement using the equation for density as a starting point.

Mass of acetone = 7.44 g (given)

Volume of acetone (v) =  mass of acetone ÷ density of acetone

V = 7.44 g ÷ 0.784 g/mL

V = 9.4897 mL

Hence volume of acetone = 9.4897 mL

To learn more about density refer the link:

brainly.com/question/6107689

#SPJ9

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The Bohr model of the atom explains the reactivity of all atoms.

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Read 2 more answers
What is the ph of a 0.006 m koh solution? 1. 11.78 2. 7.00 3. 2.22 4. 8.88 5. 5.12?
Stels [109]
The concentration of OH⁻ is first converted to pOH bu using followinf formula,

                                           pOH  =  -log [OH⁻]
Putting value,
                                           pOH  =  -log (0.006)

                                           pOH  =  2.221
As we know,
                                   pH + pOH  =  14
Solving for pH,
                                   pH  =  14 - pOH
Putting value of pOH,
                                   pH  =  14 - 2.221

                                   pH  =  11.779
Result:
           Option-1
is the correct answer.
4 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
Alex Ar [27]

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

<em>-Julie</em>

6 0
3 years ago
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