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zubka84 [21]
3 years ago
12

Please helpppppppppp

Chemistry
2 answers:
IgorC [24]3 years ago
4 0

Answer:

Plants take carbon dioxide from the air and use it to make food.

Explanation:

kipiarov [429]3 years ago
4 0

the carbon cycle is the process in which carbon travels from the atmosphere into organisms and the earth and then back into the atmosphere

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What is the average mass of a single chlorine atom in grams?
aliina [53]
It’s 5.88 x 10^-23.............
6 0
3 years ago
Read 2 more answers
How should you prepare a buret for titration before loading it with titrant?.
pochemuha

The buret should be conditioned before loading it with the titrant.

<h3>What is a Buret?</h3>

This is defined as laboratory apparatus which is used in quantitative chemical analysis to measure the volume of a liquid or a gas.

It should be conditioned with the titrant solution to prevent dilution from occurring as a result of cleaning it with water.

Read more about Buret here brainly.com/question/16996786

6 0
2 years ago
1. If you have 8.1 g CO₂ and 2.3 g H₂, which one is the limiting reactant. Show your work. 2. Calculate the theoretical yield of
ZanzabumX [31]

Answer:

2.95 g of CH₄

Explanation:

To start this, we determine the equation:

4H₂  + CO₂ →  CH₄  +  2H₂O

4 moles of hydrogen react to 1 mol of carbon dioxide in order to produce 1 mol of methane and 2 moles of water.

To determine the limiting reactant, we need to know the moles of each reactant.

8.1 g . 1 mol/ 44g = 0.184 moles of carbon dioxide

2.3 g . 1mol / 2g = 1.15 moles of hydrogen

4 moles of hydrogen react to 1 mol of CO₂

Then, 1.15 moles may react to (1.15 . 1) /4 = 0.2875 moles

We only have 0.184 moles of CO₂, so this is the limiting reactant. Not enough CO₂ to complete the 0.2875 moles that are needed.

Ratio is 1:1. 1 mol of CO₂ produces 1 mol of methane

Then, 0.184 moles of CO₂ will produce 0.184 moles of CH₄

We convert moles to mass: 0.184 mol . 16 g /mol = 2.95 g

7 0
3 years ago
Please explain why the answer is correct and why the others aren’t.<br><br> Thank you!!
Over [174]
JAJDJFR DI WIKWIKIWKWIW
8 0
3 years ago
Assume the alveolar radii are 0.05 and 0.07 mm towards the end of exhalation. Knowing that air flows from high to low pressures,
xeze [42]

Answer:

0.286 mN/m^2

Explanation:

Using Laplace's law of surface tension:

P=\frac{2T}{r}

where:

P = pressure

T = surface tension

r = radius

In the longer alveoli with radius of  0.07 mm = 0.07*10^{-2}m; we have:

P =  \frac{2*25mN/m}{0.07*10^{-2}m}

P = 0.714 mN/m^2

In the smaller alveoli with radius 0.05 mm = 0.05 * 10^{-2} m; we have:

P = \frac{2*25mN/m}{0.05*10^-2m}

P = 1.00 mN/m^2

The pressure difference can now be calculate as follows:

Pressure difference = (1.00 - 0.714)mN/m^2

Pressure difference = 0.286 mN/m^2

5 0
3 years ago
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