The relative volumes of chloroform and water that should be used is 9:10
Concentration of solution in chloroform = 
( moles of chloroform )
Concentration of solution in water = 
( moles of water )
Dissociation constant at 
; 
Concentration of solution in chloroform / Concentration of solution in water
Meaning;
Since mole is present in chloroform and mole is present in water, Total mole of Caffeine present is 
Now, we substitute our given values into the equation
Therefore, the relative volumes of chloroform and water that should be used is 9:10
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Answer:
Rate will double
Explanation:
Since the concentration of A is doubling the rate of reaction will also double, since in this scenario concentration is proportional to rate of reaction. So if the concentration of A were to triple the rate of reaction would also triple.
RbOH is a strong base that dissociates completely and HCl is a strong acid that too dissociates completely. the complete reaction between the acid and base is;
RbOH + HCl ---> RbCl + H₂O
stoichiometry of acid to base is 1:1
At neutralisation point
H⁺ mol = OH⁻ mol
mol = molarity x volume
if Ma - molarity of acid and Va - volume of acid reacted
Mb - molarity of base and Vb - volume of base reacted
Ma x Va = Mb x Vb
0.5 M x 52.8 mL = Mb x 60.0 mL
Mb = 0.44 M
molarity of base - 0.44 M
