The factors that affect geometry of a molecule are
> The number of bonding electron pairs around the central atom.
> The number of pairs of non-bonding ("lone pair") electrons around the central atom.
Your answer is correct.
MgO(s) + H2O(l) ----> Mg(OH)2(aq)
:-) ;-)
The answer is A. the solar ultraviolet ray breaks the molecule apart
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as
Mg(IO3)2
MgI2O6
As we know that
Mg has +2
O has -2
So,
(+2) + 2I + 6 (-2)=0
2 + 2I - 12 =0
10+ 2I =0
10 = 2I
I =5
The electron geometry of a water molecule is tetrahedral even though the molecular geometry is bent.
As water molecule hybridisation is sp³ that provides it a electron geometry tetrahedral but due to presence of 2 lone pairs and 2 bond pairs its molecular geometry is bent.
The hybridisation sp³ makes electron geometry of a water molecule tetrahedral but the presence of 2 lone pairs makes its molecular geometry bent
