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2 years ago

I am trying to figure out how to simplify this problem .

Mathematics

2 answers:

PIT_PIT [208]2 years ago

7 0

Answer:

Step-by-step explanation:11+12/square root of 16

11+(12/4)

11+3

answer is 14

Mashutka [201]2 years ago

7 0

Answer: 5.75

Step-by-step explanation:

(11 + 12)/ $\sqrt{16}$
According to the order of operations, we start with the square root of 16, which is 4. So:

(11 + 12)/4

Before dividing the numerator by 4, we need to add 11 and 12:
11 + 12 = 23

And 23/4 = 5.75

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The width of a rectangle is 8 cm less than its length. The perimeter of the rectangle is 52 cm.What is the width of the rectangl

astraxan [27]

Let X be width <span>of a rectangle, then
(x+8) - </span><span>length

(x+x+8)*2 = 52
x+x+8 = 52/2
2x+8 = 26
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2x = 18
x = 18/2
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Answer: 9 cm.</span>

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4 years ago

Which three side lengths best describe the triangle in the diagram?

Gala2k [10]

Answer: D, hope that helps!

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3 years ago

please help!! Assume the given triangular prism and rectangular prism have equal cross sections. Also assume the length and widt

ehidna [41]

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3 years ago

Read 2 more answers

A set of three numbers with the greatest common factor of 13

BigorU [14]

78, 130, and 91. You're welcome :D

3 0

3 years ago

Margaret is building storage boxes. each box will have a length of 8 feet, a width of 512 feet, and a height of 412 feet. a pint

Lera25 [3.4K]

The surface area of a cuboid is the area of all the six faces of a cuboid. The Paint that is required to paint 3 boxes is 13 pints.

<h3>What is the surface area of a cuboid?</h3>

The surface area of a cuboid is the area of all the six faces of a cuboid. It is given by the formula,

$\rm \text{Surface area of the box}= 2[(Length \times width)+(Width \times Height)+(Length \times height)]$

As it is given the dimensions of the storage box are a length of 8 feet, a width of 5 1/2 feet(5.5 feet), and a height of 4 1/2 feet(4.5 feet). Therefore, the surface area of the box can be written as,

$\rm \text{Surface area of the box}= 2[(Length \times width)+(Width \times Height)+(Length \times height)]$

$\rm \text{Surface area of the box}= 2[(8\times 5.5)+(5.5\times 4.5)+(8 \times 4.5)] = 209.5\ ft^2$

As it is given that the surface area that can be covered with a pint of paint is 50 square feet, therefore, the paint that will be required to paint 209 square feet is,

$\text{Paint Required} = \dfrac{\text{Total area that is needed to be paint}}{\text{Area covered in a pint of paint}}$

$\rm \text{Paint Required} = \dfrac{209.5}{50} = 4.19\ pints$

Now, we know that the surface area of the box is 209 square feet, while the paint required to paint a complete box is 4.19, therefore, the paint that will be required to paint 3 boxes will be,

$\text{Paint required to paint 3 boxes} = 3 \times 4.19 = 12.57 \approx 13$

Hence, the Paint that is required to paint 3 boxes is 13 pints.

Learn more about Surface Area of Cuboid:

brainly.com/question/26403859

4 0

2 years ago