Answer:
The correct option is b) 1.70
Step-by-step explanation:
Consider the provided information.
The weekly sulfur dioxide emissions follow a normal distribution with a mean of 1000 ppm (parts per million) and a standard deviation of 25.
Thus, μ=1000 and σ = 25
The CEO wants to know if the mean level of emissions is different from 1000.
Therefore the null and alternative hypothesis is:
and 
The sample size is n = 50 and
ppm.
Now calculate the test statistic by using the formula: 
Substitute the respective values in the above formula.


Hence, the correct option is b) 1.70
Answer: 11 degrees
Step-by-step explanation:
Answer: Simplified = 4n^2
Step-by-step explanation: the 8n and -8n cancel each other out.
we know that
1 hour is--------> 60 minutes
1 minute is---------> 60 sec
so
10 hour =10*60=600 minutes
39 sec=39/60=0.65 min
10 h 39 sec=600+0.65=600.65 min
therefore
<u>the answer is</u>
600.65 minutes
Answer: x=7
Step-by-step explanation:
(5x-40)+7 = 2
5x-33 = 2
5x = 35
x = 35/5
x = 7