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3 years ago

PLEASE HELP!!

Mathematics

1 answer:

pogonyaev3 years ago

4 0

Answer:

Work shown below!

Step-by-step explanation:

$\sqrt{-18}=\sqrt{18i^{2} } =\sqrt{2*9i^{2} }=3i\sqrt{2}$

$2\sqrt{-16} =2\sqrt{16i^{2} } =4i*2=8i$

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Which of the following is NOT a rational number?

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Answer:

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3 years ago

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A=960 rounded to the nearest 10 <br> b=89.0 rounded to 1 DP <br> Find the minimum (to 2 DP) of a÷b

astraxan [27]

Step-by-step explanation:

a÷b=960÷89=10.78651685=10.79 or 17.8

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Manuela solved the equation 3−2|0.5x 1.5|=2 for one solution. her work is shown below. 3−2|0.5x 1.5|=2 −2|0.5x 1.5|=−1 |0.5x 1.5

irakobra [83]

The other solution to the absolute value equation 3 − 2|0.5x + 1.5| = 2 is x = -4

<h3>How to determine the solution?</h3>

The equation is given as:

3 − 2|0.5x + 1.5| = 2

Subtract 3 from both sides

-2|0.5x + 1.5| = -1

Divide both sides by -2

|0.5x + 1.5| = 0.5

Expand the equation

0.5x + 1.5 = 0.5 or 0.5x + 1.5 = -0.5

Subtract 1.5 from both sides

0.5x = -1 or 0.5x = -2

Divide both sides by 0.5

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Hence, the other solution to the absolute value equation 3 − 2|0.5x + 1.5| = 2 is x = -4

Read more about absolute value equation at:

brainly.com/question/26954538

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2 years ago

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

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3 years ago

Why is ac smaller than ad if they both look very close

kakasveta [241]

Let's begin by listing out the information given to us:

We start out by observing that Triangles MKR & ACD are similar or proportional

$\begin{gathered} MK=21;AC=\text{?} \\ MR=24;AD=28\frac{4}{5} \\ KR=CD=\text{?} \end{gathered}$

We will solve for the missing side by using the similar triangle theorem. This is shown below:~

$\begin{gathered} \Delta MKR\approx\Delta ACD \\ \frac{MK}{AC}=\frac{MR}{AD} \\ \frac{21}{AC}=\frac{24}{28\frac{4}{5}} \\ \text{Cross multiply, we have:} \\ 24\cdot AC=28\frac{4}{5}\cdot21 \\ AC=\frac{28\frac{4}{5}\cdot21}{24}=25\frac{1}{5} \\ AC=25\frac{1}{5} \end{gathered}$

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1 year ago