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3 years ago

Help solving this question 5x + yb = zmh

Mathematics

1 answer:

BigorU [14]3 years ago

6 0

5X+yb=zmh
5x+yb-yb=zmh-yb
5x=zmh-yb
5x/5=zmh/5-yb/5
x=mhz-by/5

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Find the variables! please help

Morgarella [4.7K]

Answer:

x = 3, y = 5

Step-by-step explanation:

As per the diagram we got:

FH = GH = EH

As FH = 7x + 4 and EH = 9x - 2, we solve the following equation for x:

7x + 4 = 9x - 2
9x - 7x = 4 + 2
2x = 6
x = 3

So each segment is:

7*3 + 4 = 25

Therefore:

5y = 25
y = 5

So the variables are:

x = 3, y = 5

3 0

3 years ago

What is the difference?

Serhud [2]

Answer:

The option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

The difference of the given expression is

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Step-by-step explanation:

Given expression is $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

To find the difference of the given expression as below :

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-9)})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-3^2)})-({\frac{x+1}{x^2-3^2})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x-3)(x+3)})-({\frac{x+1}{(x-3)(x+3)})$

( using the formula $a^2-b^2=(a+b)(a-b)$ )

$=\frac{2x+5(x+3)-(3x+5)-x(x+1)}{x(x-3)(x+3)}$

$=\frac{2x^2+6x+5x+15-3x-5-x^2-x}{x(x-3)(x+3)}$ (adding the like terms)

$=\frac{x^2+7x+10}{x(x^2-9)}$ ( by factoring the quadratic polynomial )

$=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore the difference of the given expression is

$\frac{(x+5)(x+2)}{x^3-9x}$

Therefore option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

8 0

3 years ago

From the graph, write the linear equation in slope-intercept form

elena55 [62]

Answer:

1.y=1/2+2

2.y=-2+1

3.y=3/2+3

4.y=-2/3-2

Step-by-step explanation:

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3 years ago

The average age of three people running for election is 42. A fourth person joins the race and the average drops to 40. What is

Morgarella [4.7K]

Answer:

B. 34

$let \: sum \: of \: ages \: of\: 3 \: people \: be \: x \\ 42 = \frac{x}{3} \\ x = 126 \\ let \:age \: of \: fourth \: person \: be \: y \\ 40 = \frac{x + y}{4} \\ 160 = x + y \\ 160 = 126 + y \\ y = 34 \\ = 34 \: years$

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3 years ago

Cayden bought a total of 7 paperback books , 2 of which are biographies. What was the total cost of the 7 paperbacks if they nor

NikAS [45]

Answer:

112

7*16=112

That is the answer, hope this helps

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3 years ago

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