The highest-energy electron in a ground state atom has quantum numbers n = 4, ℓ = 1, mℓ = 0, ms = ½. this atom could be:____.
1 answer:
This atom could be bromine that has the highest-energy electron in a ground state atom has quantum numbers n = 4, ℓ = 1, = 0,
= ½.
Quantum numbers are a set of four numbers that provides complete information about an electron in an atom.
The four quantum numbers are
- Principal quantum number (n) - It tells the number of shells in which an electron resides and the maximum number of electrons in a shell.
- Azimuthal quantum number (l) - It tells the number of subshells present in a shell and the shape of orbitals
- Magnetic quantum number (
) - It tells the number of orbitals in a subshell
- Spin quantum number (
) - It tells the direction of spin of an electron on its axis.
Here, n = 4, suggests that the highest shell is 4
l = 1, suggests that the electron is in the p subshell
mℓ = 0, suggests that the electron is in the p orbital,
ms = ½ suggests that the electron has a positive spin
Electronic configuration of iron = [Ar] 3d⁶ 4s²
Electronic configuration of phosphorus = [Ne] 3s² 3p³
Electronic configuration of potassium = [Ar] 4s¹
Electronic configuration of bromine = [Ar] 4s² 3d¹⁰ 4p⁵
Electronic configuration of strontium = [Kr] 5s²
Hence, bromine is the atom that has an electron with quantum numbers n = 4, ℓ = 1, = 0,
= ½.
Disclaimer: The question is given incomplete on the portal. Here is the complete question
Question: The highest-energy electron in a ground state atom has quantum numbers n = 4, ℓ = 1, mℓ = 0, ms = ½. This atom could be
a. iron
b. potassium
c. phosphorus
d. bromine
e. strontium
Learn more about quantum numbers:
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