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Olegator [25]
3 years ago
12

3. How many moles of H20 are in 15.2 grams of pure ice?

Chemistry
1 answer:
inna [77]3 years ago
7 0

Answer:

18.01528 grams.

Explanation:

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Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your f
White raven [17]

Answer:

I am not able to click anything above!

7 0
3 years ago
What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?
lions [1.4K]

Answer:

m=33.9g

Explanation:

Hello,

In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):

Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J

Afterwards, the mass of ice that can be melted is computed by:

Q=n \Delta _{fus}H

So we solve for moles with the proper units handling:

n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol

Finally, with the molar mass of water we compute the mass:

m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g

Best regards.

7 0
3 years ago
weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the
valentinak56 [21]

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 751 mm Hg

P_2 = final pressure of gas = 495 mm Hg

V_1 = initial volume of gas = 340 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 30^oC=273+30=303K

T_2 = final temperature of gas = -27^oC=273-27=246K

Now put all the given values in the above equation, we get:

\frac{751\times 340}{303}=\frac{495\times V_2}{246}

V_2=419L

Thus the volume of the balloon at this altitude is 419 L

8 0
3 years ago
An atom of chlorine has several valence electrons in its
RUDIKE [14]
7 valence electrons in an atom

7 0
3 years ago
g A piece of solid Zn metal is put into an aqueous solution of Cu(NO3)2. Write the net ionic equation for any single-replacement
Nimfa-mama [501]

Answer:

Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)

Explanation:

Let's consider the molecular single displacement equation between Zn and Cu(NO₃)₂

Zn(s) + Cu(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Cu(s)

The complete ionic equation includes all the ions and insoluble species.

Zn(s) + Cu²⁺(aq) + 2 NO₃⁻(aq) ⇒ Zn²⁺(aq) + 2 NO₃⁻(aq) + Cu(s)

The net ionic equation includes only the ions that participate in the reaction and insoluble species.

Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)

4 0
3 years ago
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