Question

Solve for x in the equation x^2+10x+12=36

Answer 1

Answer:  The required value of x is 2 or -12.

Step-by-step explanation:  We are given to solve for x in the following equation :

$x^2+10x+12=36~~~~~~~~~~~~~~~~~~~~~~~(i)$

We will be solving the given equation by the method of factorization.

From equation (i), we have

$x^2+10x+12=36\\\\\Rightarrow x^2+10x+12-36=0\\\\\Rightarrow x^2+10x-24=0\\\\\Rightarrow x^2+12x-2x-24=0\\\\\Rightarrow x(x+12)-2(x+12)=0\\\\\Rightarrow (x-2)(x+12)=0\\\\\Rightarrow x-2=0,~~~~~~x+12=0\\\\\Rightarrow x=2,~-12.$

Thus, the required value of x is 2 or -12.

Answer 2

I am going to put the all math work for the answer of this question, but if you need an explanation for how i got each step let me know and i will provide that for you
x^2 +10x + 12 = 36
x^2 + 10x + 12 - 36 = 0
x^2 +12x - 2x - 24 = 0
x(x + 12) - 2(x +12) = 0
(x + 12) x (x - 2) = 0
x + 12 = 0
x - 2 = 0
x = -12
x = 2
your answer for the first x is x = -12, and your answer for the second x will be
x = 2 
let me know if you have any further questions
:)