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DerKrebs [107]
2 years ago
13

A particular forest is 10,000 acres. Determine its size in hectares. (1 hectare = 2.47

Chemistry
1 answer:
igor_vitrenko [27]2 years ago
8 0

Taking into account the change of units, a particular forest is 4,048.58 hectares.

<h3>Definition of rule of three</h3>

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, the direct rule of three must be applied using the following formula, where a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: x= (c×b)÷ a

The direct rule of three is the rule applied in this case where there is a change of units.

<h3>Size in hectareas</h3>

To perform in this case the conversion of units, you must first know that 1 hectare = 2.47 acres.

So, the rule of three can be used as follow: if 2.47 acres is 1 hectare, 10,000 acres equals how many hectares?

2.47 acres ⇒ 1 hectare

10,000 acres ⇒ x

So: x= (10,000 acres ×1 hectare)÷ 2.47 acres

Solving:

<u><em>x= 4,048.58 hetares</em></u>

In summary, a particular forest is 4,048.58 hectares.

Learn more with this example:

brainly.com/question/12482948

#SPJ1

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What is the freezing point (in degrees Celcius) of 3.75 kg of water if it contains 189.9 g of C a B r 2?
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Answer:

The freezing point of the solution is -1.4°C

Explanation:

Freezing point decreases by the addition of a solute to the original solvent, <em>freezing point depression formula is:</em>

ΔT = kf×m×i

<em>Where Kf is freezing point depression constant of the solvent (1.86°C/m), m is molality of the solution (Moles CaBr₂ -solute- / kg water -solvent) and i is Van't Hoff factor.</em>

Molality of the solution is:

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189.9g ₓ (1mol / 199.89g) = 0.95 moles

Molality is:

0.95 moles CaBr₂ / 3.75kg water = <em>0.253m</em>

Van't hoff factor represents how many moles of solute are produced after the dissolution of 1 mole of solid solute, for CaBr₂:

CaBr₂(s) → Ca²⁺ + 2Br⁻

3 moles of ions are formed from 1 mole of solid solute, Van't Hoff factor is 3.

Replacing:

ΔT = kf×m×i

ΔT = 1.86°C/m×0.253m×3

ΔT = 1.4°C

The freezing point of water decreases in 1.4°C. As freezing point of water is 0°C,

<h3>The freezing point of the solution is -1.4°C</h3>

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