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DerKrebs [107]
2 years ago
13

A particular forest is 10,000 acres. Determine its size in hectares. (1 hectare = 2.47

Chemistry
1 answer:
igor_vitrenko [27]2 years ago
8 0

Taking into account the change of units, a particular forest is 4,048.58 hectares.

<h3>Definition of rule of three</h3>

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, the direct rule of three must be applied using the following formula, where a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: x= (c×b)÷ a

The direct rule of three is the rule applied in this case where there is a change of units.

<h3>Size in hectareas</h3>

To perform in this case the conversion of units, you must first know that 1 hectare = 2.47 acres.

So, the rule of three can be used as follow: if 2.47 acres is 1 hectare, 10,000 acres equals how many hectares?

2.47 acres ⇒ 1 hectare

10,000 acres ⇒ x

So: x= (10,000 acres ×1 hectare)÷ 2.47 acres

Solving:

<u><em>x= 4,048.58 hetares</em></u>

In summary, a particular forest is 4,048.58 hectares.

Learn more with this example:

brainly.com/question/12482948

#SPJ1

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The second student with mass 70kg has more momentum

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Using the formula:

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According to this question, two students are running in a cross country race.

Student 1 has the following; m = 60kg, v = 7m/s

Student 2 has the following; m = 70kg, v = 7m/s

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Read 2 more answers
5 drops of 0.15 M Ki added to<br>40 drops of Na2S2O3<br>What is the final concentration of ki?​
rjkz [21]

Answer:

\boxed{\text{0.017 mol/L}}

Explanation:

Na₂S₂O₃ solution does not react with KI (it reacts with I₂), so it is simply diluting the KI, and we can use the dilution formula.

c_{1}V_{1} = c_{2}V_{2}

Data:

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V(Na₂S₂O₃) = 40 drops

Calculations:

(a) Calculate the total volume

V₂ = 5 + 40 = 45 drops

(b) Calculate the concentration

0.15 × 5 = c₂ × 45

0.75 = 45c₂

c_{2} = \dfrac{0.75 }{45} = \boxed{\textbf{0.017 mol/L}}

3 0
3 years ago
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