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Andrei [34K]
3 years ago
7

Name at least four other gases in the atmosphere besides oxygen and nitrogen

Chemistry
1 answer:
nikitadnepr [17]3 years ago
8 0
Carbon dioxide (CO2)
Argon (Ar)
Hydrogen (H)
Helium (He)
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Why does knowing types of mixtures help you to identify a substance?
Reil [10]

Answer:

This is my own explanation:

Explanation:

It is important to know the mixtures you input together because you may determine the type of substance you produced from different elements and several combinations of matter. This assists in identifying your specific substance.

8 0
2 years ago
For each molecule, specify the polarity of the bonds and the overall polarity of the molecule.
olasank [31]
Each Be–Cl bond is polar because the two atoms have different electronegativities. The number of outer atoms (2) and lone pairs on the central atom (0) indicate that this molecule has a linear geometry. The bonds in a linear molecule are symmetric, and so their dipoles cancel out.

Each O–H bond is polar because the two atoms have different electronegativities. The number of outer atoms (2) and lone pairs on the central atom (2) indicate that this molecule has a bent geometry. The bonds in a bent molecule are asymmetric, and so their dipoles do not cancel out. In addition, the asymmetric arrangement of the lone pairs on O further contribute to the dipole of this molecule.

An O–O or O=O bond is nonpolar because the two atoms have the same electronegativity. Because there is no overall polarity in O2, the molecule is nonpolar.
5 0
3 years ago
Hey there! so I have this question in chemistry where they have shown a reaction with Ammonia acid and HCL, so the question to e
lozanna [386]

What the I haven't even learned this yet

5 0
3 years ago
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∆G° for the process benzene (l) benzene (g) is 3.7 Kj/mol at 60 °C , calculate the vapor pressure of benzene at 60 °C [R=0.0821
Alex787 [66]

Answer:

4) 0.26 atm

Explanation:

In the process:

Benzene(l) → Benzene(g)

ΔG° for this process is:

ΔG° = -RT ln Q

<em>Where Q = P(Benzene(g)) / P°benzene(l) P° = 1atm</em>

ΔG° = 3700J/mol = -8.314J/molK * (60°C + 273.15) ln P(benzene) / 1atm

1.336 = ln P(benzene) / 1atm

0.26atm = P(benzene)

Right answer is:

<h3>4) 0.26 atm </h3><h3 />
6 0
3 years ago
Which reactant will be in excess, and how many moles of it will be left over?
timofeeve [1]

Answer:

Oxygen with 0.36 moles left over

Explanation:

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3 years ago
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