The ionic equation represents the element in cation and anionic form. The equation is given as OH⁻ + 2H⁺ → 2H₂O. Thus, option A is correct.
<h3>What is the ionic equation?</h3>
The ionic reaction equation is the representation of the chemicals dissociated as the ions in an aqueous solution. The ionic reaction is given as the cations and anions dissociated from the respective molecule or compound.
The ionic equation between potassium hydroxide and sulfuric acid is shown as,
2K⁺ + OH⁻ + 2H⁺ + SO₄²⁻ → 2H₂O + 2K⁺ + SO₄²⁻
It can also be written as,
Net ionic equation: OH⁻ + 2H⁺ → 2H₂O
Here, others are eliminated as they are spectator ions.
Therefore, option A. OH⁻ + 2H⁺ → 2H₂O is the net ionic equation.
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Answer:
The solution's new volume is 1.68 L
Explanation:
Dilution is the procedure to prepare a less concentrated solution from a more concentrated one, and simply consists of adding more solvent. So, in a dilution the amount of solute does not vary, but the volume of the solvent varies.
In summary, a dilution is a lower concentration solution than the original.
The way to do the calculations in a dilution is through the expression:
Ci*Vi=Cf*Vf
where C and V are concentration and volume, respectively; and the i and f subscripts indicate initial and final respectively.
In this case, being:
- Ci= 7 M
- Vi= 0.60 L
- Cf= 2.5 M
- Vf=?
Replacing:
7 M*0.60 L= 2.5 M* Vf
Solving:

Vf= 1.68 L
<u><em>The solution's new volume is 1.68 L</em></u>
Answer:
Neutralization reactions
Explanation:
A neutralization reaction is a reaction between an acid and a base. Products of this type of reaction is water and a salt. The pH of the salt product would depend on how strong or weak the base and acid would be when they react with each other. Although the characteristics of bases and acids are practically polar opposites, when combined, they cancel each other our producing a neutralized product.
Explanation:
The given data is as follows.
= 286 kJ = 
= 286000 J
,

Hence, formula to calculate entropy change of the reaction is as follows.

= ![[(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20S_%7BO_%7B2%7D%7D%29%20-%20%281%20%5Ctimes%20S_%7BH_%7B2%7D%7D%29%5D%20-%20%5B1%20%5Ctimes%20S_%7BH_%7B2%7DO%7D%5D)
= ![[(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20205%29%20%2B%20%281%20%5Ctimes%20131%29%5D%20-%20%5B%281%20%5Ctimes%2070%29%5D)
= 163.5 J/K
Therefore, formula to calculate electric work energy required is as follows.
= 
= 237.277 kJ
Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.