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Neko [114]
3 years ago
8

7. Phosphorus 32 ( 32), a radioactive isotope of phosphorus, has a half-life of 14.2 days. a. If the amount of radioactivity of

phosphorus 32 decays continuously at a constant rate, what is the decay constant? Round your answer to 4 decimal places. (10 marks) If 100 grams of this substance are present initially, determine the exponential decay function by using the decay constant found in part (a). (4 marks) c. What amount of radioactivity will be left after 6 days? Round your answer to 2 decimal places. (4 marks)
Chemistry
1 answer:
Wittaler [7]3 years ago
4 0

Explanation:

(a) Given that:

Half life = 14.2 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{14.2}\ days^{-1}

<u>The rate constant, k = 0.0488 days⁻¹ </u>

(b)Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration  = 100 g

So,  

[A_t]=100\times e^{-0.0488\times t}\ g

(c) Given t = 6 days

So,

[A_t]=100\times e^{-0.0488\times 6}\ g

<u>Amount left = 74.6171 g</u>

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What is the net ionic equation for this reaction?
Elenna [48]

The ionic equation represents the element in cation and anionic form. The equation is given as OH⁻ + 2H⁺ → 2H₂O. Thus, option A is correct.

<h3>What is the ionic equation?</h3>

The ionic reaction equation is the representation of the chemicals dissociated as the ions in an aqueous solution. The ionic reaction is given as the cations and anions dissociated from the respective molecule or compound.

The ionic equation between potassium hydroxide and sulfuric acid is shown as,

2K⁺ + OH⁻ + 2H⁺ + SO₄²⁻ → 2H₂O + 2K⁺ + SO₄²⁻

It can also be written as,

Net ionic equation: OH⁻ + 2H⁺ → 2H₂O

Here, others are eliminated as they are spectator ions.

Therefore, option A. OH⁻ + 2H⁺ → 2H₂O is the net ionic equation.

Learn more about ionic equation here:

brainly.com/question/27980783

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8 0
1 year ago
I’LL MAKE YOU BRAINLIEST+ FREE POINTS
vladimir2022 [97]

Answer:

The solution's new volume is 1.68 L

Explanation:

Dilution is the procedure to prepare a less concentrated solution from a more concentrated one, and simply consists of adding more solvent. So, in a dilution the amount of solute does not vary, but the volume of the solvent varies.

In summary, a dilution is a lower concentration solution than the original.

The way to do the calculations in a dilution is through the expression:

Ci*Vi=Cf*Vf

where C and V are concentration and volume, respectively; and the i and f subscripts indicate initial and final respectively.

In this case, being:

  • Ci= 7 M
  • Vi= 0.60 L
  • Cf= 2.5 M
  • Vf=?

Replacing:

7 M*0.60 L= 2.5 M* Vf

Solving:

Vf=\frac{7 M*0.60 L}{2.5 M}

Vf= 1.68 L

<u><em>The solution's new volume is 1.68 L</em></u>

6 0
3 years ago
Which type of reactions form salts?
Marysya12 [62]

Answer:

Neutralization reactions

Explanation:

A neutralization reaction is a reaction between an acid and a base. Products of this type of reaction is water and a salt. The pH of the salt product would depend on how strong or weak the base and acid would be when they react with each other. Although the characteristics of bases and acids are practically polar opposites, when combined, they cancel each other our producing a neutralized product.

6 0
3 years ago
Determine the electrical work required to produce one mole of hydrogen in the electrolysis of liquid water at 298°K and 1 atm. T
Ostrovityanka [42]

Explanation:

The given data is as follows.

          \Delta H = 286 kJ = 286 kJ \times \frac{1000 J}{1 kJ}

                            = 286000 J

 S_{H_{2}O} = 70 J/^{o}K,      S_{H_{2}} = 131 J/^{o}K

 S_{O_{2}} = 205 J/^{o}K

Hence, formula to calculate entropy change of the reaction is as follows.

          \Delta S_{rxn} = \sum \nu_{i}S_{i}_(products) - \sum \nu_{i}S_{i}_(reactants)

                     = [(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]

                    = [(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]

                    = 163.5 J/K

Therefore, formula to calculate electric work energy required is as follows.

             \Delta G_{rxn} = \Delta H_{rxn} - T \Delta S_{rxn}

                            = 286000 J - (163.5 J/K \times 298 K)

                            = 237.277 kJ

Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.

6 0
3 years ago
Which of the following statements is true about covalent bonds?
katrin [286]

Answer:

the answer is D.)

Explanation:

7 0
2 years ago
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