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Elena-2011 [213]
1 year ago
15

What 223 x 12 explain

Mathematics
1 answer:
geniusboy [140]1 year ago
4 0

Answer: 2676

Step-by-step explanation:

223 x 12 = 2676

This is because 223 12 times equals 2676.

*I will attach my work for the problem so you can see the solving process more clearly :).

Hope this helps :).

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Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i
Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) \frac{20i+21}{29}

(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

(b) We have given expression \frac{5-2i}{5+2i}

After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

5 0
3 years ago
Solve 5p + 10 = 8p + 1. p =​
STALIN [3.7K]

Answer:

5p + 10 = 5(p+2)

8p + 1p =​ 9p

Step-by-step explanation:

your question was confusing and you didn't specify so the first one is factored and the second is simplified.. hope it helped, brainliest please?

6 0
3 years ago
Read 2 more answers
If alpha beta are the roots of the equation
Vikki [24]

Answer:

Step-by-step explanation:

Hello, I believe that we can consider a different from 0.

By definition of the roots we can write.

ax^2+bx+c=a(x-\alpha)(x-\beta)=a(x^2-(\alpha + \beta)x+\alpha \cdot \beta)\\\\\text{So we can say that:}\\\\\alpha + \beta = \dfrac{-b}{a}\\\\\alpha \cdot \beta=\dfrac{c}{a}\\\\\text{So the expected quadratic equation is}\\\\(x+\dfrac{b}{a})(x-\dfrac{c}{a})=0\\\\ \Large \boxed{\sf \bf \ (ax+b)(ax-c)=0 \ }

Thank you

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2 years ago
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DaniilM [7]
Answer: planet c
5.7• 107
3 0
3 years ago
How do you decide which variable to isolate in order to use the substitution method to solve a system of linear equation?​
Kazeer [188]
It doesn’t really matter which variable you isolate first but usually you would use the one that’s by itself already. like for example one of the equations was y = 8. you would already have your y solve for so you would just have to plug that in for y in the other equation. personally, i usually do x first unless one of the equations has either x or y by itself already. i think its easier to just do x first and then solve for y after that, but it just depends on what the equations are; sometimes it might be easier to just do y first. hope this helps!
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2 years ago
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