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chubhunter [2.5K]
2 years ago
9

If Melinda wanted to build a patio in her backyard that was 14 feet long, 6 feet wide

Mathematics
1 answer:
JulsSmile [24]2 years ago
6 0

The volume of aggregate that she needs to build the patio is 13.18 ft^3

<h3>How many cubic feet of aggregate would she need to build the walkway?</h3>

We know that the backyard is 14ft long, 6 feet wide and 4 inches deep.

Rememeber that:

1ft = 12 in

Then:

4 in = (4/12) ft = (1/3) ft

Then the volume of the backyard is:

V = (14ft)*(6ft)*(1/3 ft) = 28ft^3

Now we know that we have a mix of 4 parts aggregate to 4.5 parts loose cement that need to fill these 28 cubic feet.

Note that:

4 + 4.5 = 8.5

How many times we have 8.5 in 28?

28/8.5 = 3.294

Now for each of these we have 4 parts of aggregate, then the volume of aggregate that we need is:

4*3.294 ft^3 = 13.18 ft^3

The volume of aggregate that she needs to build the patio is 13.18 ft^3

If you want to learn more about volumes:

brainly.com/question/1972490

#SPJ1

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3 years ago
PLEEEEEEEAAAAAAASSSSSSSSSSEEEEEEEEEEE help me!!!!!!!!!!
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Answer:

\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }

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\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}

hope this helps

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3 years ago
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