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daser333 [38]
2 years ago
10

Find the work done by a force f=8i-6j 9k that moves an object from the point (0,10,8) to the point (6,12,20) along a straight li

ne. the distance is measured in meters and the force in newtons.
Physics
1 answer:
kirza4 [7]2 years ago
4 0

Work done is 158 joule

Given that, the force of a moving object is,

F = (8i - 6j + 9k) N

The object is moving from point (0,10,8) to the point (6,12,20)

Now we can calculate the displacement by the formula,

dr = (x2-x2)i + (y2 - Y2)j + (z2 - z2)k

Put all the values from the given values.

dr = (6 - 0)x + (12 - 10)j + (20 - 8)k

dr = (6i-2j+12k) meters

Now, the work done can be calculated as,

W = F.dr

W = (8i - 6j + 9k).(6i-2j+12k)

W = 158 J

Hence, work done is 158 joule

Learn more about Work here:

brainly.com/question/25573309

#SPJ4

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Answer:

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\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411

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The conclusion of the attachment will be

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