Answer:
The value is 
Explanation:
From the question we are told that
The orbital period is 
Generally for the centripetal force acting one of the stars will be equal to the gravitational force between the stars and this can be mathematically represented as
=> 
Here m represents the mass of each star given that they have same mass and this equal to the mass of the sun whose value is
d(2 * r) is the diameter of the orbit which is distance between each star
r is the radius of the orbit
G is the gravitational constant with value 
v is the velocity of the stars which can be mathematically represented as
So
=> ![r =[ \frac{Gm T^2}{16 \pi ^2} ]^{\frac{1}{3} }](https://tex.z-dn.net/?f=r%20%3D%5B%20%20%5Cfrac%7BGm%20T%5E2%7D%7B16%20%5Cpi%20%5E2%7D%20%5D%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
=> ![r = [\frac{6.67 *10^{-11} * (1.989 *10^{30}) * 2704320^2}{16 * (3.142)^2} ]^{\frac{1}{3} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5B%5Cfrac%7B6.67%20%2A10%5E%7B-11%7D%20%2A%20%281.989%20%2A10%5E%7B30%7D%29%20%2A%202704320%5E2%7D%7B16%20%2A%20%283.142%29%5E2%7D%20%5D%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
=> 
Generally the distance between the star is
=> 
=>
<h2>
Answer:</h2>
400N/m
<h2>
Explanation:</h2>
When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e
= ∑ⁿ₁ [
] -----------------------(i)
That is;
= 
+ 
+ 
+ . . . + 
-------------------(ii)
If they have the same value of stiffness say s, then equation (ii) becomes;
= n x 
-----------------(iii)
Where;
n = number of springs
From the question,
There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;
n = 3
s = 1200N/m
Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;
= 3 x 
= 
= 
Cross multiply;
m = 400N/m
Therefore, the stiffness of the longer spring is 400N/m
Answer:
I've combined both answers on a single graph.
Explanation:
The acceleration of the race car is 6 m/s²
The given parameters;
initial velocity of the race car, u = 6 m/s
final velocity of the race car, v = 36 m/s
time of motion, t = 5 s
Acceleration is defined as the change in velocity per change in time of motion.
The acceleration of the race car is calculated as follows;
Thus, the acceleration of the race car is 6 m/s²
Learn more here: brainly.com/question/17280180
Using v=u+at, Where v is final velocity(m/s), u is initial velocity(m/s), a is acceleration(m/s^2) and t is time(s).
v = 0 + 3.2*6
v=19.2 m/s.
