What is the magnitude of the electric force on an electron in a uniform electric field of strength 2050 n/c that points due east
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Answer:
P.E = 4.398 Joules.
Explanation:
Given the following data;
Spring constant, k = 71.8N/m
Displacement, x = 0.35m
To find the elastic potential energy;
The elastic potential energy of an object is given by the formula;
Substituting into the equation, we have;
Elastic potential energy = 4.398 Joules.
<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>