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katrin [286]
3 years ago
14

On Wednesday afternoons, eight men play tennis on two courts. They know ahead of time which four will play on the north court an

d which four will play on the south court. The players arrive randomly at the tennis courts. What is the probability that the first four players that arrive are all assigned to (a)the north court, and (b)the same court
Mathematics
2 answers:
Bond [772]3 years ago
7 0

Answer:

50% for both

Step-by-step explanation:

but otherwise b they will go to the farthest court so the others can go to the closest coart

musickatia [10]3 years ago
6 0

Answer:

(A)

Step-by-step explanation:

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4 Student is 20% of ____ students
luda_lava [24]

Answer:

4 Student is 20% of 20 students

Step-by-step explanation:

if 4 = 20% then 1 = 5% to get a hundred percent then you need to multiply by 20

so 20

4 Student is 20% of 20 students

5 0
3 years ago
Read 2 more answers
3 Jazmin is mailing two packages. One package weighs 3 pounds, and the other package weighs 20 ounces. What is the total weight
Angelina_Jolie [31]

Answer:

68oz

Step-by-step explanation:

1) 3lbs x 16oz = 48

Now we know 3lbs is 48oz. since one pound is 16 ounces, 3 pounds is 48 ounces.

2) 48 + 20 = 68oz

3) The total weight of both packages is 68 ounces.

Jesus loves ya, have a great day!

---------------------

John 8:12 - When Jesus spoke again to the people, he said, "I am the light of the world. Whoever follows me will never walk in darkness, but will have the light of life."

8 0
2 years ago
Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp
yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

H_0: \mu=2\\\\H_a:\mu< 2

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803

The degrees of freedom for this sample size are:

df=n-1=52-1=51

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0
2 years ago
The answer using Pythagorean theorem
OverLord2011 [107]

Answer: 12.32 is the answer.


Step-by-step explanation: Using the pythagorean thereom we can solve this by using the formula A^2+B^2=C^2.

We substitute in the values,

17^2+B^2=21^2.

Now we simplify.

289+B^2=441

We subtract the 289 from both sides,

B^2=152                                                                                                                                                            

Now we use square root to find the answer.

12.32 is the answer.

Hope this helps!


5 0
3 years ago
What is the value of ​2×[34−5×(3+1)]​ ?
spayn [35]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{28}}}}}

Step-by-step explanation:

Use BODMAS rule :

Bracket , Of , Division , Multiplication , Addition , Subtraction

\sf{2 \times [ 34 - 5 \times (3 + 1) ] }

Add the numbers : 3 and 1

\dashrightarrow{ \sf{2 \times [ 34 - 5 \times 4 ] }}

Multiply the numbers : 5 and 4

\dashrightarrow{ \sf{2 \times [ 34  - 20 \: ]  }}

Subtract 20 from 34

\dashrightarrow{ \sf{2 \times 14}}

Multiply the numbers : 2 and 14

\dashrightarrow{ \sf{28}}

Hope I helped!

Best regards! :D

4 0
3 years ago
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