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Anarel [89]
1 year ago
11

How do you convert the decimal 0.24 to fraction in the simplest form

Mathematics
1 answer:
RideAnS [48]1 year ago
6 0

Answer:

0.24---> 24/100 --->  6/25

Step-by-step explanation:

hope that helps

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Which of the following functions best describes this graph?
ValentinkaMS [17]

Answer: y=x^2+7x+10

Step-by-step explanation: apex

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Can someone explain how to do this step by step please Order Of Operations: Parentheses in PEMDAS
guapka [62]

Answer:

3/4 or 0.75

Step-by-step explanation:

logic

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Multiply.<br> (3b-5) (7b+1)<br> Simplify your answer.
mylen [45]
<h3>Answer:</h3>

It would be 21b² -32b -5

<h3>Step-by-step explanation:</h3>

By using the FOIL method, you can simplify the equation.

<em>The Foil Method is </em><u><em>ac + ad + bc +bd</em></u><em>, or </em><u><em>First, Outer, Inner, Last.</em></u>

First, you multiply the first term in each bracket.

3b * 7b = 21b²

Next, you multiply the outer term in each bracket.

3b * 1 = 3b

Then, you multiply the inner term in each bracket.

-5 * 7b = -35b

After that, you multiply the last term in each bracket.

-5 * 1 = -5

Lastly, you combine like terms.

21b² + 3b -35b -5 ---> 21b² -32b -5

<em>21b² -32b -5 would be your answer, since you cannot simplify the equation anymore.</em>

7 0
3 years ago
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

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